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Shalnov [3]
3 years ago
12

WHICH OF THE FOLLOWING IS THE COEFFICIENT IN THE ALGEBRAIC EXPRESSION 12X+Z>4

Mathematics
2 answers:
Phantasy [73]3 years ago
3 0

the answer is z mate because 12 and 4 are numbers

const2013 [10]3 years ago
3 0

Answer:

It would be the Z

Step-by-step explanation:

This is because a coefficient is a letter by itself and the only letter by itself is the z :) Hope this helps!

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The formula y y-y1=m(x-x1) please tell me what is m
grandymaker [24]

Answer:

There is no value in M

Step-by-step explanation:

The equation is undefined.

6 0
4 years ago
Write the equation in y-intercept form slope 2 passes through point (5,-2)
Alenkinab [10]
<h2>Answer</h2>

The equation is y = 2x - 12

<h2>Explanation</h2>

Equation in slope intercept form is

y = mx + b

Where,

m = slope

b = y-intercept

Putting the value of slope in this equation:

y = 2x + b

From this we can solve the equation for b

b = y - 2x

b = -2 - 2(5)

b = -12

Now, the equation of y-intercept becomes

y = 2x - 12


5 0
4 years ago
HELP DUE IN 10 MINUTES WILL GIVE BRAINLEST!!
Pachacha [2.7K]

y-intercept: (0, 7)

x-intercept: (-\frac{7}{4},0)\\

5 0
3 years ago
Read 2 more answers
Find the compound interest compounded annually on rupees 2700 rate 6 ⅔% per annum and time is 2 years​
dalvyx [7]

<u>Answer:</u>

plz mark me as brainliest ...TOOK ME LONG TIME TO TYPE

answer = CI = 3108 RUPEES

<u>Step-by-step explanation:</u>

i am doing the method in which u find the simple interest of first year then second year.

SI FOR 1ST YEAR= P X R X T / 100

SI = 2700 X 20 X 2 / 3 X 100   ( RATE OF INTEREST IS 20 / 3)

SI = 108000/300

SI = 360

SI FOR SECOND YEAR =

P = 2700 + 360= 3060

SI = 3060 X 20 X 2 / 300

SI= 122400 / 300

SI = 408

COMPOUND INTEREST (CI) = PRINCIPLE + SI OF 2ND YEAR

CI = 2700 + 408

CI = 3108 RUPEES

or u can solve be the method

CI = amount - principle

Amount= principle x (change in ratio) raised to time

                                       ***************************************

6 0
3 years ago
What is the length of segment BC? A coordinate plane is shown. Point B is located at negative 3, negative 2, and point C is loca
Mrac [35]
The length of segment BC can be determined using the distance formula, wherein, d = sqrt[(X_2 - X_1)^2 + (Y_2 - Y_1)^2]. The variable d represent the distance between the two points while X_1, Y_1 and X_2, Y_2 represent points 1 and 2, respectively. Plugging in the coordinates of the points B(-3,-2) and C(0,2) into the equation, we get the length of segment BC equal to 5.  
4 0
4 years ago
Read 2 more answers
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