Answer:
The equilibrium quantity is 26.4
Step-by-step explanation:
Given
Required
Determine the equilibrium quantity
First, we need to determine the equilibrium by equating Qd to Qs
i.e.
This gives:
Collect Like Terms
Solve for P
This is the equilibrium price.
Substitute 2.4 for P in any of the quantity functions to give the equilibrium quantity:
<em>Hence, the equilibrium quantity is 26.4</em>
<span>Find the exact value of sec(-4π/3). Note that one full rotation, clockwise, would be -2pi. We have to determine the Quadrant in which this angle -4pi/3 lies. Think of this as 4(-pi/3), or 4(-60 degrees). Starting at the positive x-axis and rotating clockwise, we reach -60, -120, -180 and -240 degrees. This is in Q III. The ray representing -240 has adj side = -1 and opp side = to sqrt(3).
Using the Pyth. Theorem to find the length of the hypo, we get hyp = 2.
Thus, the secant of this angle in QIII is hyp / adj, or 2 / sqrt(3) (answer). This could also be written as (2/3)sqrt(3).
</span>
The sequence above is geometric progression.
The nth term of such sequence is given by;
Tn = ar∧(n-1),
Where a⇒first term and
r⇒common ratio
So, 1st term = 5×1.25∧(1-1) = 5×1.25∧0 =5
2nd term = 5×1.25∧(2-1) = 5×1.25 = 6.25
3rd term = 5×1.25∧(3-1) = 5×1.25² = 7.8125
4th term = 5×1.25∧(4-1) =5×1.25³ = 9.765625
5th term = 5×1.25∧(5-1) = 5×1.25∧4 = 12.20703125
6th term = 5×1.25∧(6-1) = 5×1.25∧5 = 15.25878909
1) 8
2) 6(5x+2y) factor out greatest common factor
3) 10.8 just move over decimal two places to the left.
4) 30t=150? Then t=5kg Im not sure what the last one is asking, but I’m assuming it’s to solve for t.
Parentheses first
9q-14+3q-3(8)=7
9q-14+3q-24=7
Combine like terms
9q + 3q - 14 - 24 = 7
12q -38=7
add 38 to both sides
12q - 38 + 38 = 7 + 38
12q = 45
divide both sides by 12
q = 45/12
q = 3.75
