2 - 2 * 0 ≤ 1
<span>2 ≤ 1 </span>
<span>4 - 2 * (-2) ≤ 1 </span>
<span>8 ≤ 1 </span>
<span>4 - 2 * (1) ≤ 1 </span>
<span>2 ≤ 1 </span>
<span>0 - 2 * 5 ≤ 1 </span>
<span>-10 ≤ 1 </span>
<span>(TRUE</span>
Answer:
![\sqrt[3]{x^{2}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D)
Step-by-step explanation:
![x^{2/3} = \sqrt[3]{x^{2}}](https://tex.z-dn.net/?f=x%5E%7B2%2F3%7D%20%3D%20%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D)
Let
x-------> the number of dinner
y-------> the number of lunch
we know that
-------> equation A
------> equation B
Substitute equation B in equation A
![8[y]+5y \leq 42](https://tex.z-dn.net/?f=8%5By%5D%2B5y%20%5Cleq%2042)



so
the greatest number of lunch is 

Hence
the greatest number of dinner is 
therefore
the greatest number of meals is

<u>the answer is</u>
