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dezoksy [38]
3 years ago
7

Car rentals involve a $130 flat fee and an additional cost of $31.67 a day what is the maximum number of days you can rent a car

if you have a $500 budget
Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
8 0
The equation is $130 + $31.67x = 500
Subtract 130 from both sides $31.67x = $370
Divide $31.67 from both sides
X=11.68
BUT
you can’t have .68 of a day so the answer is 11 days.
qaws [65]3 years ago
5 0
The Maximum number of days you can rent a car if you only have a $500 budget is 11 days.
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Dhani has 4 cards numbered 1 through 4. He removes 2 cards at random and adds their values.
DanielleElmas [232]

Answer:

2/3

Step-by-step explanation:

The total number of sums (not distinct) is 4\cdot 3=12, because we're removing without replacement.

Count the sums that fit the stipulation (sum \leq 5):

1,2,\\2,1\\1,3\\3,1\\1, 4\\4, 1\\2, 3, \\3,2

There are 8 sums that work. Therefore, the desired answer is \frac{8}{12}=\boxed{\frac{2}{3}}

3 0
2 years ago
Evaluate 3 to the 2nd power plus 7 times 2
Olin [163]

Hey there!

3^2 + 7 • 2

3^2 = 3 • 3 = 9

9 + 7 • 2

7 • 2 = 14

9 + 14 = 23

Answer: 23 ☑️

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

7 0
3 years ago
Read 2 more answers
Why would a box and whisker plot be unequal?
bearhunter [10]
Becasue the data may be skewed right or left (not symmetrical)

that is obvious when the median lean to left or right while the maximum and minimum records are still as they are.
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4 0
3 years ago
Help on this please.
dem82 [27]

Answer:

x = 46°

Step-by-step explanation:

the opposite angles of a cyclic quadrilateral are supplementary, sum to 180° , then

x + 134° = 180° ( subtract 134° from both sides )

x = 46°

8 0
1 year ago
If x square plus 8x plus q =(x plus k) Square find the value of k and q​
PIT_PIT [208]

Answer:

The value of k is 4 and q is 16.

Step-by-step explanation:

First, you have to expand the brackets by applying :

{(a + b)}^{2}  =  {a}^{2}  + 2ab +  {b}^{2}

{x}^{2}  + 8x + q =  {(x + k)}^{2}

{x}^{2}  + 8x + q =  {x}^{2}  + 2kx +  {k}^{2}

Next, you have to do it by comparison :

{x}^{2}  + 8x + q =  {x}^{2}  + 2kx +  {k}^{2}

by \: comparison

8x = 2kx

8 = 2k

k = 4

q =  {k}^{2}

q =  {4}^{2}

q = 16

7 0
3 years ago
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