the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
The amount of substance left of a radioactive element of half life,

after a time, t, is given by:

Given that <span>potassium-40 has a half life of approximately 1.25 billion
years.
The number of years it will take for 0.1% of potassium-40 to remain is obtained as follows:

Therefore, </span><span>the maximum age of a fossil that we could date using 40k is
12.5 billion years.</span>
Answer: What expression can Melanie write to figure out how much her ... Mauricio plans on retiring in 20 years, and he wants to double his money by that time. He has contacted various banks, looking for a CD that compounds interest monthly, and to calculate what annual interest rate he needs, he is using the rule of 72.
Step-by-step explanation: I did what I could man
Don't lie about your age and 32oz+(2*128)=32oz+256=288oz
Answer:
a) 0.35
b) 420 drawing pins
Step-by-step explanation:
a) The question relates to the relative frequency of the pins pointing up which is found by the formula as follows;

The total number of pins land 'point up' = 3 + 5 + 6 + 2 + 4 + 7 + 3 + 3 + 4 + 5
The total number of pins land 'point up' = 42 successful trials
Total number of trials = 12 × 10 = 120 trials

Due to the large number of trials, the relative frequency ≈ Probability and the probability that a single pin will land point up = 7/20 = 0.35
b) Given that the number of trials now = 12 × 100 = 1200, we have;
The expected number of drawing pins in total that would land point up = 0.35×1200 = 420 pins.