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Ymorist [56]
3 years ago
8

Kiana wants to write equations in the form y = mx + b for the lines passing through

Mathematics
1 answer:
horrorfan [7]3 years ago
3 0

Answer:

'Substitute the slope and the coordinates of point P(-3,2) in y = mx + b and then solve for b in each equation'.

Step-by-step explanation:

Kiana wants to write equations in the form y = mx + b for the lines passing through point P that are parallel and perpendicular to line q.  

This equation is in the slope-intercept form where m is the slope and b is the y-intercept.

First, she finds the slope of line q and the slope of line s to be – 2. Point P is located at (-3,2).

Therefore, the step that can be used to find the y-intercept is 'substitute the slope and the coordinates of point P(-3,2) in y = mx + b and then solve for b in each equation'. (Answer)

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A group of high school athletes has an average GPA of 2.7 with a standard deviation of 0.9. a)Find the percentage of athletes wh
mart [117]

Answer:

a) The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is 3.645.

Step-by-step explanation:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

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a)Find the percentage of athletes whose GPA more than 1.665.

This is 1 subtracted by the pvalue of Z when X = 1.665. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.665 - 2.7}{0.9}

Z = -1.15

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The percentage of athletes whose GPA more than 1.665 is 87.49%.

b) John's GPA is more than 85.31 percent of the athletes in the study. Compute his GPA.

His GPA is X when Z has a pvalue of 0.8531. So it is X when Z = 1.05.

Z = \frac{X - \mu}{\sigma}

1.05 = \frac{X - 2.7}{0.9}

X - 2.7 = 1.05*0.9

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