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Natalka [10]
3 years ago
8

Solve the inequality k+8-2(k-12)>0

Mathematics
2 answers:
Serggg [28]3 years ago
7 0
I think it k < -32 pretty sure
LiRa [457]3 years ago
6 0
Step by step;

K+8-2(k-12)>0
K+8-2k+24>0
-K+32>0
-K>-32
K<32
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Can the sum of three consecutive integers be even? Give some examples to support your Answer.
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Write the decimal 1.822 as a fraction. Do not write in lowest terms.
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Answer to your problem is:

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yuradex [85]
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3 0
2 years ago
A=bx+cx/2<br><br> please help
andreyandreev [35.5K]

Answer:

I'm too tired to explain, here's some digital work on a site called Symbolab:

5 0
3 years ago
Please help and thank you
kondaur [170]

Answer:

Step-by-step explanation:

Let's see how well I can explain this. \frac{\pi}{6} is the same as a 30 degree angle which is in quadrant 1. If you picture the unit circle, right in the center of it is the origin. If you draw a straight line from 30 degrees and through the center (the origin), you will automatically "connect" with the reference angle of 30 (this is true for ALL angles on the unit circle). This puts us in quadrant 3. In quadrant 3, x is negative and so is y. So the terminal point of the reference angle for 30 degrees has the same exact values, but both of them are negative (again, because both x and y are negative in quadrant 3). I can't see your choices but the one you want looks like this:

(-\frac{\sqrt{3} }{2},-\frac{1}{2})

3 0
2 years ago
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