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Keith_Richards [23]
3 years ago
15

10 POINTS!! HELP ASAP!! What is the length of AC?

Mathematics
2 answers:
il63 [147K]3 years ago
8 0

Answer:

D.  144

Step-by-step explanation:

Triangle BAC is similar to triangle DEC, so you can set up a ratio:

\frac{84}{156-x} = \frac{7}{x}

Then cross multiply

84x = 7 (156 - x)

84x = 1092 - 7x

Add 7x to both sides.

91x = 1092

Divide both sides by 91.

x = 12

AC = 156 - x

AC = 156 - 12

AC = 144

My name is Ann [436]3 years ago
4 0

Answer:

D

Step-by-step explanation:

Δ CED and Δ CAB are similar thus the ratios of corresponding sides are equal, that is

\frac{CE}{CA} = \frac{ED}{AB} , substitute values

\frac{x}{156-x} = \frac{7}{84} = \frac{1}{12} ( cross- multiply )

12x = 156 - x ( add x to both sides )

13x = 156 ( divide both sides by 13 )

x = 12

Thus

AC = 156 - x = 156 - 12 = 144 → D

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Answer:

n - 324 = 394

STEP BY STEP EXPLANATION

5 0
3 years ago
What is an equation of the line that passes through the points (-6, 5) and (6, 7)?
e-lub [12.9K]

Answer:

y=\frac{1}{6}x+6

Step-by-step explanation:

Let (x_1,y_1)\rightarrow(-6,5) and (x_2,y_2)\rightarrow(6,7)

<u>Determine slope</u>

<u />m=\frac{y_2-y_1}{x_2-x_1}\\ \\m=\frac{7-5}{6-(-6)}\\ \\m=\frac{2}{6+6}\\ \\m=\frac{2}{12}\\ \\m=\frac{1}{6}

<u>Use either ordered pair to find the y-intercept</u>

<u />y=mx+b\\\\7=\frac{1}{6}(6)+b\\\\7=1+b\\\\6=b

<u>Final equation</u>

<u />y=\frac{1}{6}x+6

4 0
2 years ago
Which solution set describes the solutions to the inequality below?
Nuetrik [128]
<h2>Hello!</h2>

The answer is:

The sixth option,

[-6,6]

<h2>Why?</h2>

To solve the problem, we need to find which of the given options match with the solution to the inequality. As we know, solving inequalities is almost the same that solving equalities, we need to isolate the variable and then, find where it satisfies the given condition (inequality)

So, solving the inequality we have:

-3x^{2} +1\leq -107\\-3x^{2}\leq -107-1\\-3x^{2} \leq -108\\3x^{2} \leq 108\\x^{2} \leq \frac{108}{3}\\\sqrt{x^{2} } \leq \sqrt{36}\\ x^{2\leq } +-36\\(x-6)(x+6)\leq 0

Therefore, we have that the solutions to the inequality are:

First solution:

x-6\leq 0\\x\leq 6

Second solution:

x+6\leq 0\\x\leq-6

Hence, the correct option is the sixth option, the solution is described by the following solution set :

[-6,6]

Have a nice day!

7 0
3 years ago
Write an absolute value inequality that
fiasKO [112]

Answer:

All real numbers greater than or equal to -1 and less than or equal to 2

Step-by-step explanation:

Let

A_1 ------> the area of rectangle

A_2 ----> the area of triangle

we know that

\left|A_1-A_2\right|\le 6

<em>Find out the area of rectangle</em>

A_1=4(x+2)=(4x+8)\ units^2

<em>Find out the area of triangle</em>

A_2=(1/2)(4)(5)=10\ units^2

substitute

\left|(4x+8)-10\right|\le 6

Simplify

\left|4x-2\right|\le 6

<em>First case (positive value)</em>

+(4x-2) \leq 6

4x \leq 6+2

4x \leq 8

x \leq 2

<em>Second case (negative value)</em>

-(4x-2) \leq 6

Multiply by -1 both sides

(4x-2) \geq -6

(4x \geq -6+2

4x \geq -4

x \geq -1

therefore

The solution for x is the interval -----> [-1,2]

All real numbers greater than or equal to -1 and less than or equal to 2

8 0
3 years ago
Evaluate −12(−2). (1 point) a 14 b −14 c −24 d 24
nalin [4]

Answer:

d.24

Step-by-step explanation:

12*2=24 and a negative times a negative always equals a positive.

8 0
3 years ago
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