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3 years ago

I need help!

Mathematics

2 answers:

Andrej [43]3 years ago

8 0

Answer: divide both numbers with 266 at the front like this 266÷10

Step-by-step explanation:

26.6

xenn [34]3 years ago

5 0

Answer:

2260 in^2

Step-by-step explanation:

scaled basically means multiplied by

so 226 times 10 is 2260

dont forget your units or you will get it wrong

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if u play ro-b-lox blox-burg, answer!! dont answer if u dont.. but is it fair if i say abc tk help me make snowmans and each sno

Papessa [141]

Answer:

You probably should have gave them 2/3 of what they did. I wouldn't call you a scammer, but it was not fair.

3 0

3 years ago

Which number is halfway between

Anarel [89]

You are looking for the average. To find the average, one adds all terms and divides by the number of terms.
((1/2)+(5/6))/2
((3/6)+(5/6))/2
(8/6)/2
(4/6)
(2/3)
The answer is B) 2/3.

6 0

3 years ago

You want to buy a camera. The retail price is $75. The camera is on sale for 15% off . What is the sale price of the camera?

ludmilkaskok [199]

Answer:

$63.75

Step-by-step explanation:

15% off

Get percentage of retail price

1-0.15 = .85

0.85 = 85%

The sale price is 85% of the retail price

Multiply

0.85 * 75

$63.75

7 0

2 years ago

1) 7+a=15 2) 23=d+44 3) 28=n-14 4) T-22=-31

Romashka [77]

Hi, I'd be glad to help.

1) a = 8

2) d = (-21)

3) n = 42

4) t = (-9)

6 0

3 years ago

Read 2 more answers

Students in a zoology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After t

juin [17]

Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

$\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}$

e. Maximum of the function

The maximum of the function is at t= 0.

Max = 73 %

The graph below shows your knowledge decay curve. Knowledge decays rapidly at first but slows as time goes on.

6 0

3 years ago