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3 years ago

I need help!

Mathematics

2 answers:

Andrej [43]3 years ago

8 0

Answer: divide both numbers with 266 at the front like this 266÷10

Step-by-step explanation:

26.6

xenn [34]3 years ago

5 0

Answer:

2260 in^2

Step-by-step explanation:

scaled basically means multiplied by

so 226 times 10 is 2260

dont forget your units or you will get it wrong

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if I rent a boat for $25 per hour and a charge additionally $12 for fuel is the number of hours I rent the boat proportional to

andrew11 [14]

Yes, that is because they go in the same direction, for instance, you rent it longer, the price increases accordingly.

8 0

3 years ago

If I buy a sweatshirt for $30, and the sales tax is 7% in my state, how much will I pay for the sweatshirt, including the sales

algol13

Answer:

$32.10

Step-by-step explanation:

If you have sales tax, you would first convert the percentage to decimal, or 0.07. Then you would take this number, and add it to one before you multiply it by the price of the sweatshirt. This makes sure that you're not just calculating the sales tax, but the overall price of the shirt. So if you multiply:

30 x 1.07 = 32.1

Add the units, and you get $32.10

Hope this helps!

6 0

3 years ago

Read 2 more answers

Which graph represents the function y=3x^2+2

alexira [117]

None, you wrote a different function than the one in the picture.

The answer to the picture is the last graph

4 0

3 years ago

Read 2 more answers

Practice Writing Trig Ratios

Ierofanga [76]

Answer:

13.) tanC=40/30

14.) tanA=21/20

15.) tanC=12/35

16.) tanX=30/40

17.) sinZ=12/37

18.) sinZ=30/50

4 0

4 years ago

The true average diameter of ball bearings of a certain type is supposed to be 0.05 in. A one-sample t-test will be carried out

satela [25.4K]

Answer:

a) H0: $\mu \leq \mu_o$

H1: $\mu > \mu_o$

n = 13 represent the sample size

$t = 1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12} >1.6) = 0.068$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

b) H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 13 represent the sample size

$t = -1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12}$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

c) H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 25 represent the sample size

$t = -2.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 25-1=24$

We can calculathe the p value with this formula:

$p_v = P(t_{24}$

Since $p_v$ we can reject the null hypothesis on this case at 1% of significance.

Step-by-step explanation:

Part a

For this case we assume that we are testing the following system of hypothesis

H0: $\mu \leq \mu_o$

H1: $\mu > \mu_o$

n = 13 represent the sample size

$t = 1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12} >1.6) = 0.068$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

Part b

For this case we assume that we are testing the following system of hypothesis

H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 13 represent the sample size

$t = -1.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 13-1=12$

We can calculathe the p value with this formula:

$p_v = P(t_{12}$

Since $p_v >\alpha$ we fail to reject the null hypothesis on this case at 5% of significance.

Part c

For this case we assume that we are testing the following system of hypothesis

H0: $\mu \geq \mu_o$

H1: $\mu < \mu_o$

n = 25 represent the sample size

$t = -2.6$ represent the calculated statistic

The degrees of freedom are given by:

$df = n-1 = 25-1=24$

We can calculathe the p value with this formula:

$p_v = P(t_{24}$

Since $p_v$ we can reject the null hypothesis on this case at 1% of significance.

8 0

3 years ago