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Fittoniya [83]
3 years ago
15

what is the number smaller than 100 larger than 50 is not divisible by five and is even it and it's divisible by three

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
5 0
40
is the answer thank you
alexandr1967 [171]3 years ago
4 0
I believe it could be 69 ?
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Each equation below is followed by several stories.
zloy xaker [14]
Not sure sorry edit : oh sorry I was suppose to add this in the comment section
7 0
3 years ago
Please help me with the below question.
Snezhnost [94]

6a. By the convolution theorem,

L\{t^3\star e^{5t}\} = L\{t^3\} \times L\{e^{5t}\} = \dfrac6{s^4} \times \dfrac1{s-5} = \boxed{\dfrac5{s^4(s-5)}}

6b. Similarly,

L\{e^{3t}\star \cos(t)\} = L\{e^{3t}\} \times L\{\cos(t)\} = \dfrac1{s-3} \times \dfrac s{1+s^2} = \boxed{\dfrac s{(s-3)(s^2+1)}}

7. Take the Laplace transform of both sides, noting that the integral is the convolution of e^t and f(t).

\displaystyle f(t) = 3 - 4 \int_0^t e^\tau f(t - \tau) \, d\tau

\implies \displaystyle F(s) = \dfrac3s - 4 F(s) G(s)

where g(t) = e^t. Then G(s) = \frac1{s-1}, and

F(s) = \dfrac3s - \dfrac4{s-1} F(s) \implies F(s) = \dfrac{\frac3s}{\frac{s+3}{s-1}} = 3\dfrac{s-1}{s(s+3)}

We have the partial fraction decomposition,

\dfrac{s-1}{s(s+3)} = \dfrac13 \left(-\dfrac1s + \dfrac4{s+3}\right)

Then we can easily compute the inverse transform to solve for f(t) :

F(s) = -\dfrac1s + \dfrac4{s+3}

\implies \boxed{f(t) = -1 + 4e^{-3t}}

6 0
1 year ago
Find the answer 10 + (45 x 2)
levacccp [35]

Answer:

100

Step-by-step explanation:

10 + 45*2

10 + 90

100

5 0
3 years ago
Read 2 more answers
1/7 divided by 3<br> Is it 1/3 or 1/2 im so confuse
larisa86 [58]
<h3><u>given</u><u>:</u></h3>

<u>\frac{1}{7}   \div 3</u>

<h3><u>solution</u><u>:</u></h3>

<u>\frac{1}{7}  \div  \frac{3}{1}</u>

<u>\frac{1 \times 1}{7 \times 3}</u>

<u>=  \frac{1}{21}</u>

5 0
2 years ago
Find the midpoint of JK if J(-7. -5) and K(-3,7).
qaws [65]

Answer:

( − 5 , 1 )

Step-by-step explanation:

Use the midpoint formula to find the midpoint of the line segment.

7 0
3 years ago
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