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tatiyna
2 years ago
7

Line AB passes through points A (-6,6) and B(12,3). If the equation of the line is written in slope-intercept form, y=mx+b, the.

m=-16. What is the value of b?
Mathematics
1 answer:
Tomtit [17]2 years ago
3 0

Answer:

You wrote the question wrong...

m is not -16 it is -1/6 (that is a big difference)

y=mx+b

y=-1/6x+b

3 = -1/6(12) + b

3 = -2 + b

b=5

Step-by-step explanation:

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PLEASE HELP !!!!!!!!!!! WILL MARK BRIANLIEST !!!!!!!!!!!!!
Igoryamba

Answer:

3:2

Step-by-step explanation:

I'd say 3:2 because when you divide 45/30, you get 3/2, which is the same as 3:2. Hope this helps!

4 0
3 years ago
Read 2 more answers
A gift shop sells 140 wind chimes per month at $90 each. The owners estimate that for each $5 increase in price, they will sell
guapka [62]

Answer: $95

Step-by-step explanation:

Te new price will be 90 + 5x, if the price increases "x" times

The number of wind chimes sold per month will become 140 - 7x

\begin{aligned}&\text {Revenue, } \mathrm{R}(\mathrm{x})=(90+5 \mathrm{x})(140-7 \mathrm{x}) \\&R^{\prime}(x)=5(140-7 x)-7(90+5 x) \\&R^{\prime}(x)=700-35 x-630-35 x \\&R^{\prime}(x)=70-70 x=0 \\&70 x=70 \\&x=1\end{aligned}

Therefore, if the price becomes (90 + 5(1)) = $95 per wind chime, then the revenue will be maximum

6 0
2 years ago
Which of the following does not satisfy the inequality 3(x + 4) − x > 4?
stealth61 [152]

Answer:

B

Step-by-step explanation: It's B because -4 isn't greater than -4 it is the same number, and the symbol isn't greater than or equal to it is just greater than. Your answer is B.

5 0
3 years ago
The position vector of p (relative to the origin) is op = (x, y). if the magnitude of op is 5 units, find the set of all possibl
Firdavs [7]

Answer:

S = {(0, 5), (0, - 5), (3, 4), (3, -4), (-3, 4), (-3, -4), (4, 3), (4, -3), (-4, 3), (-4, -3), (5,0), (-5, 0) }

Step-by-step explanation:

Remember that the distance between two points (a, b) and (c, d) is given by:

distance = \sqrt{(a - c)^2 + (b - d)^2}

So, here we have that the distance between the point (x, y) and the origin, (0, 0) must have a magnitude of 5 units, then we want to solve:

5 = \sqrt{(x - 0)^2 + (y - 0)^2} \\5 = \sqrt{x^2 + y^2}

If we square both sides, we get

5^2 = (\sqrt{x^2 + y^2} )^2\\25 = x^2 + y^2

Now we want to find all the points (x, y) that meet this condition, suc that:

x ∈ Z

y ∈ Z

So both x and y must be integers.

So here we can just play with different values of x and y.

For example, if we define:

x = 0 we get:

25 = 0^2 + y^2

25 = y^2

√25 = y

Then we can have y = 5 or  y = -5

from this we got two points:

(0, 5) and (0, - 5)

if x = 1 we have:

25 = 1^2 + y^2

25 - 1 = y^2

24 = y^2

There is no integer such that its square is equal to 24, so we can stop here.

if x = 2 or - 2, we have:

25 = 2^2 + y^2

25 = 4 + y^2

25 -4 = 21 = y^2

Again, there is no integer such that its square is equal to 21, so we can stop here.

if x = +3 or -3, we have:

25 = 3^2 + y^2

25 = 9 + y^2

25 - 9 = 16 = y^2

√16 = y

then we can have y = 4 or y = -4

from this we got four points:

(3, 4)

(-3, 4)

(3, -4)

(-3, -4)

And for symmetry, if x = 4 or -4 we have the points:

(-4, 3)

(4, 3)

(-4, -3)

(4, -3)

finally, again for symmetry, if we take x = 5 or x = -5 we have the points:

(5,0)

(-5, 0)

Concluding, the set of all possible values (x, y) is:

S = {(0, 5), (0, - 5), (3, 4), (3, -4), (-3, 4), (-3, -4), (4, 3), (4, -3), (-4, 3), (-4, -3), (5,0), (-5, 0) }

7 0
3 years ago
Add Polynomials<br> (3y + y^3– 5) + (4y– 4y + 2y^3+ 8)
nexus9112 [7]

Step-by-step explanation:

Please refer to the attachment

8 0
3 years ago
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