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Ber [7]
3 years ago
10

) Suppose you are installing a wood floor in a square room. The cost to install the floor is $9 per square foot. The area of the

room is given by the function A(x) = x 2 and the cost per square foot is given by the function C(A) = 9A. Which function can be used to find the total cost to install the wood floor? A) A(C(x)) B) C(A(x)) C) x(A(C)) D) x(C(A))
Mathematics
1 answer:
ratelena [41]3 years ago
8 0

Answer:

The correct option is;

B) C(A(x))

Step-by-step explanation:

The given information are;

The cost to install the floor per square foot = $9

The area of the room is given by the function A(x) = x²

The function for the cost per square foot = C(A) = 9·A

We note that the total cost to install the wood floor = (The cost to install the floor per square foot) × (The area of the room)

∴ The total cost to install the wood floor = $9 × x²

Given that A(x) = x², we have;

The total cost to install the wood floor = $9 × A(x)

Also, given that C(A) = 9·A, we have;

C(A(x)) = 9·A(x)

Therefore;

The total cost to install the wood floor in dollar amount can be given by the function, C(A(x)) = 9·A(x)

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An employer wishes to compare typing speeds of graduates from 2 different study programs: A and B. Eight random graduates from c
Karolina [17]

Answer:

Calculated value t =  0.614< 1.782

we accepted null hypothesis for 12 degrees of freedom at 0.05 level of significance .

<u>Step-by-step explanation:</u>

<u>we will t-test </u> t = x⁻- y⁻ /S√ n₁+n₂-2

Given An employer wishes to compare typing speeds of graduates from 2 different study programs: A and B

course A type at 62, 85, 59, 64, 73, 70, 75, and 72

mean of x is x⁻ = ∑x / n

mean of x = 62+85+59+64+73+70+75+ 72 /8 = 70

x⁻ = 70

course B type at 75, 64, 81, 55, 69, and 58

mean of y is  y⁻ = ∑y / n = 75+64+81+55+69+ 58/6 = 67

y⁻ =67

course A    course B

    x                    y             x- x⁻     (x-x⁻ )^2     y- y⁻     (y-y⁻ )^2    

    62                75            8             64          8            64

    85                64           15            225       -3             9

    59                81           -11            121          14            196      

    64                55           -6            36          -12          144          

    73                69          3                9            2            4

    70               58            0              0           -9            81

    75                              5              25

    72                              2               4

                                            ∑( (x-x⁻ )^2= 484           ∑( (y-y⁻ )^2= 498

Adding ∑( (x-x⁻ )^2+ ∑( (y-y⁻ )^2= 982

n₁+n₂-2 = 8+6-2=12

now S^2 =  982/ 12 =81.833

<u>Null hypothesis :H₀:μ₁=μ₂ ( there is no difference between A and B)</u>

<u>Alternative hypothesis :H₁:μ₁≠μ₂</u>

<u>level of significance ∝=0.05</u>

<u>we will use t-test </u> t =   0.614 ( see attachment )

The degrees of freedom = n₁+n₂-2 = 8+6-2=12

From tabulated value  t = 1.782

Calculated value t = 0.614< 1.782

we accepted null hypothesis for 12 degrees of freedom at 0.05 level of significance .

There is no difference between Course A and Course B

Download docx
8 0
3 years ago
Solve for x and then find the measure of ZB
VARVARA [1.3K]

Answer:

Step-by-step explanation:

angle A = angle B (because they are alternate exterior angles)

8x+6=4x+38

8x-4x=38-6

4x=32

x=32/4

x=8

For angle A

8x+6

8*8+6

64+6

70

For angle B

4x+38

4*8+38

32+38

70

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3 years ago
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gayaneshka [121]

Answer:

146 + ( - 39 + x) = 180 \\ 146 - 39 + x = 180 \\ 107 + x = 180 \\ x = 180 - 107 \\ x = 73

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3 years ago
I need help please!!
mina [271]

Step-by-step explanation:

11

\frac{ - 1}{5}  \times  \frac{4}{7}

\:  \:  \:  \:  \:  \frac{ - 4}{35}

12

\frac{ - 1}{2}  \times  \frac{4}{5}

\frac{ - 2}{5}

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\frac{ - 3}{2}  \times  \frac{7}{ - 10}

\frac{21}{20}

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\frac{1}{2}  \times  \frac{7}{8}

\frac{7}{16}

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\frac{ - 9}{5}  \times   \frac{1}{2}

\frac{ - 9}{10}

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\frac{ - 32}{9}  \times  \frac{1}{3}

\frac{ - 32}{27}

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\frac{ - 2}{1}   \div \frac{ - 19}{5}

\:  \:  \:  \:  \:  \: \frac{ - 2}{1}  \times  \frac{5}{ - 19}

\:  \:  \:  \:  \frac{ - 10}{19}

18

\frac{1}{9}  \div  \frac{ - 4}{3}

\frac{1}{9}  \times  \frac{3}{ - 4}

\frac{ - 1}{12}

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\frac{13}{7}  \div  \frac{23}{4}

\frac{13}{7}  \times  \frac{4}{23}

\frac{52}{161}

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5 0
3 years ago
Read 2 more answers
During the election for class president, 120 of the students voted for Lindsay, and 280 of the students voted for sharif. 400 St
prisoha [69]

Answer:

x=200

Step-by-step explanation:

let 'x' represent the total number of students

0.40x of the students voted for Gerardo

0.35x of the students voted for Leandro

0.25x of the students voted for Juju

70 students voted for Leandro:

0.35x = 70

by solving we find:

x = 200 students

5 0
3 years ago
Read 2 more answers
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