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lara31 [8.8K]
3 years ago
6

What is the absolute value of 1/2?

Mathematics
1 answer:
harina [27]3 years ago
7 0

The Absolute Value of a number is "the magnitude of a real number without regard to its sign". So the Absoulute Value of 1/2 is |1/2|

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A family buys a studio apartment for $240,000. They pay a down payment of $60,000.
stealth61 [152]

Answer:

Part A: 25%
Part B: 40%

Step-by-step explanation:

Given the following questions:

$240000 for a studio apartment
$60000 as a down payment.

In order to find the answer, we use the formula to calculate the percentage for the total cost of the studio apartment and the down payment.


<u>Part A:</u>
\frac{c\times n}{100}
\frac{25\times240000}{100} =25\times240000=60000
=60000

<u>Part B:</u>
\frac{c\times n}{100}
\frac{40\times240000}{100} =40\times240000=9600000\div100=96000
=96000

The percent of a down payment of $60,000 for a $240,000 studio apartment is "25%." While the percent of a $96,000 dollar down payment for a $240,000 studio apartment is "40%."

Hope this helps.

8 0
3 years ago
I NEED YOUR OPINION PLEASE
lys-0071 [83]

You're gonna get caught anyways, just come out. If you don't, figure out a way to undo it.

6 0
3 years ago
Whatsapp is 500% in a fraction in the simplest form
PolarNik [594]
500%=0.5 which is equal to 1/2 so the answer is 1/2

8 0
4 years ago
Read 2 more answers
Find the​ mean, variance, and standard deviation of the binomial distribution with the given values of n and p. n equals 125n=12
sesenic [268]
<span>This is a matter of knowing the formulas involving the binomial distribution: Mean = n*p = 125*0.46 = 57.5
 Variance = n*p*(1-p) = 125*0.46*(1-0.46) = 125*0.46*0.54 = 31.05
 Standard Deviation = sqrt(Variance) = sqrt(31.05) = 5.572252686</span>
7 0
4 years ago
good evening! Can someone please answer this, ill give you brainliest and your earning 50 points. Would be very appreciated.
AVprozaik [17]

Answer:

<u>Part 1</u>

Set B

<u>Part 2</u>

We can use the FOIL method to multiply these expressions:

\textsf{FOIL}: \quad(a+b)(c+d)=ac+ad+bc+bd

However, as all the expression are in the format (a+b)^2, we can use the shortcut:  (a+b)^2=a^2+2ab+b^2

<u>Part 3</u>

Using the shortcut to find the products:

\begin{aligned}\implies (x+5)(x+5)& =(x+5)^2\\ & =x^2+2(x)(5)+5^2\\ & =x^2+10x+25\end{aligned}

\begin{aligned}\implies (2x+9)(2x+9) & = (2x+9)^2\\ & = (2x)^2+2(2x)(9)+9^2\\ & = 4x^2+36x+81\end{aligned}

\begin{aligned}\implies (x+1)^2 & = x^2+2(x)(1)+1^2\\ & = x^2+2x+1\end{aligned}

<u>Part 4</u>

A new example of a multiplication problem based on the structure of Set B is:  (3x+2)(3x+2)

\begin{aligned}\implies (3x+2)(3x+2) & = (3x+2)^2\\ & = (3x)^2+2(3x)(2)+2^2\\ & = 9x^2+12x+4\end{aligned}

<u>Part 5</u>

An example of a multiplication problem that would NOT be included in Set B based on its structure is: (x+2)(x-2)

We cannot use the derived Set B shortcut (from part 2) to multiply this expression.  Instead, we would have to use a different shortcut of "The Difference of Two Squares" to find the product of this example expression.

5 0
2 years ago
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