How do you write 600,000,000,000 40,000,000 9,000,000 50,000 8,000 100, 2 in standard form?
Likurg_2 [28]
Count the number of 0
1. 6×10^11
2. 4×10^7
3. 9×10^6
4. 5×10^4
5. 8×10^3
6. 1×10^2
7. 2
2x2(2x+1)(2x-1) this is the answer I got.
Let n be the first integer and n + 1 the next consecutive integer
5n + (n + 1)
6n + 1
Answer:
Step-by-step explanation:
subtract 160 from both sides, you get -178, 2d divided by -178 is -89 so you get d=-89.
