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2 years ago

50 POINTS !! PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.

Mathematics

1 answer:

schepotkina [342]2 years ago

6 0

Answer: 17mm

Step-by-step explanation:

$c\sqrt{15^{2}+8^{2} } =17$

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a store sells small notebooks for $7 and large notebooks for $14. if a student buys 6 note books for $63, how many notebooks eac

bija089 [108]

The answer is 3 of each. 3X7=21; 14X3=42, and 42+21= 63.

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3 years ago

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In the figure, PA and PB are tangent to circle O and PD bisects ∠BPA . The figure is not drawn to scale. For m

Mademuasel [1]

Angle AOC = 46° Find angle BPO

We have congruent right triangles PAO and PBO, right angles A and B.

So AOC=BOC=46 degrees,

PBO is a right angle so BPO is complementary to BOC, so 42 degrees

Answer: 42 degrees

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2 years ago

I NEED help for like the millionth time. like i said thanks to everyone who is answering my questions. but click her please if u

12345 [234]

I think it’s answer A

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2 years ago

It takes Dwight 1 1/3 hours to run the sunshine trail. Mike 3 1/5 hours to walk the same trail. How many times as long does it t

Anit [1.1K]

For this case we convert the mixed numbers to fractions:

Dwight: $1 \frac {1} {3} = \frac {3 * 1 + 1} {3} = \frac {4} {3} = 1.33$

Mike: $3 \frac {1} {5} = \frac {5 * 3 + 1} {5} = \frac {16} {5} = 3.2$

It is observed, that in fact, Mike takes more time to travel the road.

We subtract to know how much more time it takes Mike:

$\frac {16} {5} - \frac {4} {3} = \frac {48-20} {15} = \frac {28} {15}$

So, Mike takes $\frac {28} {15}$ hours more than Dwight to walk the road.

Answer:

Mike takes $\frac {28} {15}$ hours longer than Dwight to walk the road.

7 0

2 years ago

I was walking to the store at the same time as my friend Angela. No matter what, She has always gotten there twice as fast as me

atroni [7]

Let's call your speed "a"

her walking speed is then "2a"

and her friend's scooter speed is 10 a

let's also call the distance you need to walk "d"

so the time (t)you need is:

d/t=a
t=d/a

and her time is:
t= $\frac{d}{2} /2a+ \frac{d}{2} /10a$
(half a distance with the speed of 2a and half a distance (d/2) with the distance of 10 a

now we count (we know that her time is 30 minutes)

30= $\frac{d}{4a}+\frac{d}{20a}$ //multiply by 20a

600a= $5d+d$
600a=6d/divide by 6
100a=d

Now, in order to calculate your time we need to calculate:

t=d/a

but we know how much is d now!
t= $\frac{100a}{a}$ =100

which means that you need 100 minutes, or 1 h 40 minutes!!!

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2 years ago