Find f(5) for this sequence:

The correct answer is: 
we cannot take an even root of a negative number in the real number system.

Explanation: 
A rational exponent is another way of writing a root. The denominator of the rational exponent will be the root, and the numerator will be the power of the number under the root. If the denominator is even, this means we are taking an even root, such as square root, 4th root, etc.
If the base is negative, this means we want an even root of a negative number.
Any even root can be broken down into a series of square roots, done one after another.
However, we cannot take the square root of a negative number using real numbers; this is because a square root is a number multiplied by itself to get the answer; a negative times a negative is a positive, as is a positive times a positive, so there is no way to multiply the same number twice and get a negative.

5 0

3 years ago

Read 2 more answers

More hypotheses Write the null and alternative hypotheses you would use to test each situation.

Annette [7]

Answer:

The null and alternative hypotheses are shown below:

Part (a) $H_0: p=0.40\\H_a: p\neq 0.40$

Part (b) $H_0: p=0.20\\H_a: p< 0.20$

Part (c) $H_0: p=0.60\\H_a: p> 0.60$

Step-by-step explanation:

Consider the provided information.

We need to write the null and alternative hypotheses.

Part (a) In the 1950s, only about 40% of high school graduates went on to college.

The null hypotheses is 0.40 and alternative hypotheses is about 0.40 but not equal to 0.40.

$H_0: p=0.40\\H_a: p\neq 0.40$

Part (b) Twenty percent of cars of a certain model have needed costly transmission work after being driven between 50,000 and 100,000 miles. The manufacturer hopes that a redesign of a transmission component has solved this problem.

20% Cars need costly transmission and manufacture hopes that redesign of a transmission component solved this problem.

Thus, the null hypotheses is 0.20 and alternative hypotheses less than 0.20 because after redesign less than 0.20 cars needs transmission.

$H_0: p=0.20\\H_a: p< 0.20$

Part (c): We field-test a new-flavor soft drink, planning to market it only if we are sure that over 60% of the people like the flavor.

We planning to market it only if 0.60 of the people like the flavor.

Thus, the null hypotheses is 0.60 and alternative hypotheses greater than 0.60.

$H_0: p=0.60\\H_a: p> 0.60$

3 0

3 years ago

Factor expression given the polynomial 49x^2 + 100

weqwewe [10]

Answer: