Evaluate the expression 2m+2n if m=9 and n=3

Mathematics

2 answers:

tatuchka [14]3 years ago

4 0

Just substitute each number in for the variables: 9 for m and 3 for n.

2m+2n
= 2(9)+2(3)
= 18+6
= 24

VashaNatasha [74]3 years ago

4 0

Substitute m and n values into the expression.
2(9)+2(3)
18+6= 24
24 is your answer.

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3 years ago

Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact

umka2103 [35]

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The permutation formula is expressed as

$\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\ \end{gathered}$

The combination formula is expressed as

$\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\ \\ \end{gathered}$

where

$\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}$

Given that 6 objects are taken at a time from 8, this implies that

$\begin{gathered} n=8 \\ r=6 \end{gathered}$

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Number of permuations:

$\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}$

Number of combinations:

$\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}$

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7 0

1 year ago

1 - 2x = -x - 3 what is the answer?

cricket20 [7]

Isolate the variable x.
1-2x=-x-3
1=x-3
x=4

4 0

3 years ago

Read 2 more answers

An item is regularly priced at $40 . Milan bought it at a discount of 45% off the regular price. How much did Milan pay?

maw [93]

45%=.45
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40-18=22