Answer:
115%(15,800)= $18,170. <--- markup price
$15,800+$18,170= $33,970 total price
That is 115% x $15,800 = $18,170 markup price
Then add the original price to the markup price
That is $15,800 + $18,170 = $33,970
The equation of the line parallel to given line and passing through (-3, 1) will be y – 1 = (3/2)(x + 3). Then the correct option is D.
<h3>What is the equation of line?</h3>
The equation of line is given as
y = mx + c
Where m is the slope and c is the y-intercept.
The slope of the parallel lines are equal.
m = (2 + 4) / (2 + 2)
m = 6/4
m = 3/2
Then the equation of the line will be
y = (3/2)x + c
The line is passing through (-3, 1). Then the value of c will be
1 = (3/2)(-3) + c
c = 9/2 + 1
Then the equation will be
y = (3/2)x + 9/2 + 1
y – 1 = (3/2)(x + 3)
Then the correct option is D.
More about the equation of line link is given below.
brainly.com/question/21511618
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So 12.44 hours=460.28 oz
divide
so
oz/hour means hour=1 so divide
460.28/12.44=37/1
the answer is 36 fluid ounces per hour
A) The membership cost starts at $23 and it adds $6 every year. The 23 would be your b and the 6 would be your slope, m, in the form y=mx+b.
y=6x+23
This equation means that you're starting at 23 dollars and adding 6 dollars with every x you add.
B) 2009-1995=14 This means that there's 14 years that the cost increased. 14*6=$84 The membership cost increased by anther $84 over the 14 years. You have to add 84 to 23 to find your total=$107.
C) Set $85 equal to 6x+23
85=6x+23
6x=62
x≈10
10 years later the cost will be $85.
1995+10=2005
Check the picture below.
well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.
bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.
![\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}](https://tex.z-dn.net/?f=%5Cbf%20A%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20B%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B1%7D%29%20~%5Chfill%20%5Cstackrel%7Bslope%7D%7Bm%7D%5Cimplies%20%5Ccfrac%7B%5Cstackrel%7Brise%7D%20%7B%5Cstackrel%7By_2%7D%7B1%7D-%5Cstackrel%7By1%7D%7B4%7D%7D%7D%7B%5Cunderset%7Brun%7D%20%7B%5Cunderset%7Bx_2%7D%7B5%7D-%5Cunderset%7Bx_1%7D%7B1%7D%7D%7D%5Cimplies%20%5Ccfrac%7B-3%7D%7B4%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bslope%20of%20AB%7D%7D%7B-%5Ccfrac%7B3%7D%7B4%7D%7D%5Cqquad%20%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Ctextit%7B%5Cunderline%7Bnegative%20reciprocal%7D%20and%20slope%20of%20the%20diameter%7D%7D%7B%5Ccfrac%7B4%7D%7B3%7D%7D)
so, it passes through the midpoint of AB,
so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)
