All categories

2 years ago

Please answer this correctly

Mathematics

1 answer:

Jlenok [28]2 years ago

4 0

Answer:

Answer: 75.4 or 75.398. So we can plug in the formula pi*r^2*h. R being radius and h being height. So then we can put and get pi*2^2*6 = pi*4*6 = pi*24 = 75.398 = 75.40.

<h2><u>Therefore the answer is 75.40 and not close to 301, the radius is not 4 but 2. They're giving diameter and not radius.</u></h2>

You might be interested in

14/2 three equivalent ratios

Anna71 [15]

Answer:

Three equivalent ratios of $\frac{14}{2}$ are $\frac{7}{1}$ , $\frac{21}{3}$ and $\frac{28}{8}$ .

Step-by-step explanation:

We are given a fraction $\frac{14}{2}$ .

We need to find the three equivalent ratios/fractions of $\frac{14}{2}$ .

The common factor of 14 and 2 is 2.

So, dividing top and bottom by 2, we get

14÷2 = 7 and 2÷2 that is $\frac{7}{1}$ .

Multiplying $\frac{7}{1}$ fraction by a common number 3 in top and bottom, we get

7 × 3 = 21

1 × 3 = 6

So, we get another equivalent fraction $\frac{21}{6}$ .

Multiplying $\frac{7}{1}$ fraction by a common number 3 in top and bottom, we get

7 × 4 = 28

1 × 4 = 4

So, we get another equivalent fraction $\frac{28}{4}$ .

Therefore, three equivalent ratios of $\frac{14}{2}$ are $\frac{7}{1}$ , $\frac{21}{3}$ and $\frac{28}{4}$ .

6 0

3 years ago

Please help. Simplify 6^-3/6^-5

melomori [17]

Answer:

36.

Step-by-step explanation:

Please correct me if i'm wrong! :)

7 0

2 years ago

Read 2 more answers

A survey showed that 77% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 22 adults are

Sveta_85 [38]

Answer:

The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight correction .

Step-by-step explanation:

A survey showed that 77% of adults need correction for their eyesight.

If 22 adults are randomly selected, find the probability that no more than more than 11 of them need correction for their eyesight.

n =22

p = 0.77

q = 1-p = 1- 0.77=0.23

We are supposed to find $P(x\leq 11)$

$P(x\leq 11)=P(x=1)+P(x=2)+P(x=3)+.....+P(x=11)$

Formula : $P(x=r)=^nC_r p^r q^{n-r}$

$P(x\leq 11)=^{22}C_1 (0.77)^1 (0.23)^{22-1}+^{22}C_2 (0.77)^2 (0.23)^{22-2}+^{22}C_3 (0.77)^1 (0.23)^{22-3}+.....+^{22}C_{11} (0.77)^1 (0.23)^{22-11}$