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Orlov [11]
3 years ago
9

Which statement best explains whether the table represents a linear or nonlinear function?

Mathematics
1 answer:
dalvyx [7]3 years ago
7 0

Answer:

C

Step-by-step explanation:

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What is the answer if 202^2 base3 - 112^2 base3?
yuradex [85]

Answer:

Hello,

answer is 204 in base 10 or 21120 in base 3

Step-by-step explanation:

((202)_3)^2=(202*202)_3=(112211)_3\\\\((112)_3)^2=(112*112)_3=(21021)_3\\\\(112211-21021)_3=(211120)_3=(204)_{10}\\\\\\\\\\Other\ way\\\\((202)_3)^2=((20)_{10})^2=(400)_{10}\\\\((112)_3)^2=((14)_{10})^2=(196)_{10}\\\\(400-196)_{10}=(204)_{10}=(21120)_3

6 0
3 years ago
In △ABC, G is the centroid. If CG=12 find CD.
VladimirAG [237]

Answer:

CD = 24

Step-by-step explanation:

If G is the centroid, then CG = GD. (12 = 12)

Since CD is CG and GD combined, we would just add these two numbers to find the total length of CD.

CG + GD = CD

12 + 12 = 24

5 0
2 years ago
What values of x satisfy the equation 2x^2 -3x +4 =0
BaLLatris [955]

Answer:

(3 ± √23 * i) /4

Step-by-step explanation:

To solve this, we can apply the Quadratic Equation.

In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)

Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4

Plugging these values into our equation, we get

x = (-b ± √(b²-4ac))/(2a)

x = (-(-3) ± √(3²-4(2)(4)))/(2(2))

= (3 ± √(9-32))/4

= (3 ± √(-23))/4

= (3 ± √23 * i) /4

6 0
3 years ago
Is it possible to draw a triangle whose angles measure 50°, 50°, and 80°?
Firdavs [7]
First of all, we know a quality of all interior angles of a triangle, they should add to 180 degrees. 

Does 50+50+80 degrees give 180 degrees? 

100+80=180 degrees 

Therefore, yes, it is possible to draw a triangle with the angle measures given to be 50, 50 and 80 degrees. 

Hope I helped :) 
5 0
3 years ago
Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$
Blizzard [7]
\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}

a^{81}\equiv1^{81}\equiv1\pmod7

b^{91}\equiv2^{91}\pmod7

2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7
8\equiv1\pmod7
2\equiv2\pmod7
\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7

c^{27}\equiv6^{27}\pmod7

6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7

\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7
6 0
3 years ago
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