#2: 4 cans : $2.36 = 13 : $7.67 SCALE FACTOR: $7.67 divided by $2.36 = 3.25
Use the SF to multiply the missing information.
So 4 cans x 3.25 = 13

YOU CAN BUY 13 CANS FOR $7.67

#4: 2 eggs: 1 1/2 cups of eggs : 10 pancakes = : : 35 pancakes

SCALE FACTOR: 35 pancakes divided by 10 pancakes= 3.5
Use the SF to multiply the missing information
So: 2 eggs x 3.5 = 7

7 EGGS WILL BE NEEDED TO MAKE 10 PANCAKES

#6: 54 pounds: 1 acre = pounds: 12.5 acres

SCALE FACTOR: 12.5 divided by 1 acre= 12.5
Use the SF to find out the mussing information
So, 54 pounds x 12.5 = 675 pounds

THE FARMER CAN HARVEST 675 POUNDS WITH 12.5 ACRES OF FIELD

#8: 90 miles: 120 minutes (5 hours) = 225 miles : 300 minutes (5 hours)

SCALE FACTOR: 225 miles divided by 90 miles = 2.5
Use the SF to figure out the missing information
So, 120 minutes multiplied by 2.5 = 300 minutes (5 hours)

IT WILL TAKE 5 HOURS TO DRIVE 225 MILES

4 0

3 years ago

Find the value of x

devlian [24]

X=20
180=7x+x+20
-20. -20
180=7x+x
180=8x
divide by 8
x=20

5 0

3 years ago

What is the volume of a cylinder that has the following measurements? area of each base: 50.24 ft2 area of lateral surface: 75.3

Andrew [12]

Answer:

150.72 ft³

Step-by-step explanation:

<u>Given:</u>

Area of the base :

B = 50.24 ft²

Height of cylinder:

h = 3 ft

<u>The volume is:</u>

V = Bh
V = 50.24*3 = 150.72 ft³

5 0

3 years ago

Read 2 more answers

Evaluate the integral from 0 to 1/2 of xcospixdx

aleksklad [387]

$\bf \int\limits_{0}^{\frac{1}{2}}xcos(\underline{\pi x})\cdot dx\\
-----------------------------\\
u=\underline{\pi x}\implies \frac{du}{dx}=\pi \implies \frac{du}{\pi }=dx\\
-----------------------------\\
thus\implies \int\limits_{0}^{\frac{1}{2}}xcos(u)\cdot \cfrac{du}{\pi }
\\\\
\textit{wait a sec, we need the integrand in u-terms}\\
\textit{what the dickens is up with that "x"?}\qquad well\\
-----------------------------\\
u=\pi x\implies \frac{u}{\pi }=x\\
-----------------------------\\$ $\bf thus
\\\\
\int\limits_{0}^{\frac{1}{2}}\cfrac{u}{\pi }cos(u)\cdot \cfrac{du}{\pi }\implies 
\int\limits_{0}^{\frac{1}{2}}\cfrac{u}{\pi }\cdot \cfrac{cos(u)}{\pi }\cdot du\implies 
\cfrac{u}{\pi^2}\int\limits_{0}^{\frac{1}{2}}cos(u)\cdot du\\
-----------------------------\\
\textit{now, let us do the bounds}
\\\\
u\left( \frac{1}{2} \right)=\pi\left( \frac{1}{2} \right)\to \frac{\pi }{2}
\\\\
u\left( 0 \right)=\pi (0)\to 0\\
-----------------------------\\$ $\bf thus
\\\\
\cfrac{u}{\pi^2}\int\limits_{0}^{\frac{\pi }{2}}cos(u)\cdot du\implies \cfrac{u}{\pi^2}\cdot sin(u)\implies \left[ \cfrac{u\cdot sin(u)}{\pi^2} \right]_{0}^{\frac{\pi }{2}}
$

5 0

3 years ago