L = the length of the property
W = the width of the property
Area
L * W = 6
but it says," The width of the property is of 3/8 the length he property."
therefore
W = 3%2F8L
or
W = .375L
In the area equation, replace W with .375L
L * .375L = 6
.375L^2 = 6
L^2 = 6%2F.375
L^2 = 16
L = sqrt%2816%29
L = 4 mi is the length
then
.375(4) = 1.5 mi is the width
Answer:
The answer you want is indeed, (C).
8.04
ED2021
The answer is 3(2x-5) (x+12)
1. use the equation y -y1 = m(x-x1)
2. (-6,-4) is x1,y1 and (4,-6) is x2,y2
3. y-(-4) = m(x-(-6)
m is the gradient, 10/10, which is 1. make two negatives into a positive.
4. y+4 = x+6
therefore the equation of the lines is y = x+2
substitute the points back into the equation to double check.
The area of the field where the length of each side is increased by 10% is 48.4
.
Step-by-step explanation:
The given is,
A rectangle field has an area of 40 
If one side of the field is 3 cm longer than the other side
The length of new area in each side is increased by 10%
Step:1
Let,
- One side of rectangle
- Other side of rectangle
From given.
-
+3
Formula for area of rectangle,
40 = ( b+3) × b
40 =
+ 3b
Solving the above the equation,
b = 5 cm
l = 8 cm
Step:2
If the area of rectangle increased by 10%,
l = 8 + ( 8 ×
)
= 8.8
b = 5 + ( 5 ×
)
= 5.5
Area of rectangle is,
a = ( 8.8 × 5.5 )
= 48.4 square centimeters
Result:
The area of the field where the length of each side is increased by 10% is 48.4
, if a rectangle field has an area of 40 square centimeters and one side of the field is 3 cm longer than the other side.