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Nookie1986 [14]
3 years ago
6

A 25 gram sample of a sample that's used for drug research has a k value of 0.1205

Mathematics
1 answer:
ra1l [238]3 years ago
4 0
N=12.5(at time t=t) Here half life
No=25
K=12.05
Simple exponential equation where you need to calculate
Your answer should be 5.75225876
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Which of the following is equivalent to the expression below?
AlekseyPX

Answer:

h

Step-by-step explanation: j

4 0
2 years ago
Help!!!!! Not the top one by the way..!
OverLord2011 [107]

Answer:

\large\boxed{x=-3\ and\ y=-11\to(-3,\ -11)}

Step-by-step explanation:

\underline{+\left\{\begin{array}{ccc}-6x+y=7\\3x-y=2\end{array}\right}\qquad\text{add both sides of the equations}\\\\.\qquad-3x=9\qquad\text{divide both sides by (-3)}\\.\qquad\boxed{x=-3}\\\\\text{Put the value of x to the first equation:}\\\\-6(-3)+y=7\\18+y=7\qquad\text{subtract 18 from both sides}\\\boxed{y=-11}

3 0
3 years ago
Hurry show your work
Nikolay [14]

Answer: \huge\boxed{\boxed{15}}

Step-by-step explanation:

<u>Given expression</u>

\large\boxed{\frac{12[30 - (9+4^2)]}{|10|-|-6| } }

<u>Simplify the exponents</u>

\large\boxed{=\frac{12[30 - (9+16)]}{|10|-|-6| } }

Simplify values in the parenthesis

\large\boxed{=\frac{12[30 - 25]}{|10|-|-6| } }

\large\boxed{=\frac{12[5]}{|10|-|-6| } }

<u>Simplify absolute values (all positive)</u>

\large\boxed{=\frac{12[5]}{10-6 } }

\large\boxed{=\frac{12[5]}{4 } }

<u>Simplify by division</u>

\large\boxed{=3~[5]}

<u>Simplify by multiplication</u>

\huge\boxed{\boxed{=15}}

Hope this helps!! :)

Please let me know if you have any questions

7 0
1 year ago
Solve 900•6 in steps
77julia77 [94]

Answer:5400

Step-by-step explanation:9•6= 54

Add both zeros from 900 at the end and it’s 5400

7 0
3 years ago
Read 2 more answers
The rabbit population in a forest area grows at the rate of 5% monthly. If there are 150 rabbits in September, find how many rab
egoroff_w [7]
I think 240..
September to next September=12months
the population grows at the rate of 5% so
5×12=60%
150×60%=90
90+150=240

i dont know if im right but...
8 0
3 years ago
Read 2 more answers
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