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2 years ago

A 25 gram sample of a sample that's used for drug research has a k value of 0.1205

1 answer:

4 0

N=12.5(at time t=t) Here half life
No=25
K=12.05
Simple exponential equation where you need to calculate
Your answer should be 5.75225876

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Whats two times four

Alisiya [41]

Answer:

8. rhdvevshbsbbdbdsbsbzjzjd

4 0

2 years ago

Read 2 more answers

central high's marching band has 75 members and the band from northeast high has 90 members. during the halftime show the bands

Bas_tet [7]

Answer:

The answer would be 0.83 repeated decmal

Step-by-step explanation:

All you got to do is divide the two numbers and it'd give you 0.83 repeated decmal

5 0

1 year ago

Last summer, Marrero was at Newgrange, a stone mound in Ireland that has a diameter of 250 feet. He found a walkway 62 feet long

timofeeve [1]

Answer:

108 ft

Step-by-step explanation:

The line connecting the center with the end of the walkway is radius and is the hypotenuse of the right triangle.

Horizontal leg is the distance x.

<u>Vertical leg has the length:</u>

(250)/2 - 62 = 63 ft

<u>Using Pythagorean theorem to find the length of x:</u>

x² = (250/2)² - 63²
x² = 125² - 63²
x² = 11656
x = √11656
x = 107.96 ≈ 108

7 0

2 years ago

2. Solve the system of equations. Write your answer in parametric vector notation. X, +5x2 + 4x3 + 3x4 +9xs = 18 2x, +6x2 + 4x3

ratelena [41]

Answer:

The system is inconsistent.

Step-by-step explanation:

The system is

$x_1+5x_2+4x_3+3x_4+9x_5=18\\2x_1+6x_2+4x_3+6x_4+6x_5=28\\3x_1+7x_2+4x_3+10x_4+x_5=41\\4x_1+6x_2+2x_3+7x_4+4x_5=29$

The associated matrix to the system is

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\2&6&4&6&6&28\\3&7&4&10&1&41\\4&6&2&7&4&29\end{array}\right]$

Now we use row operations to find the echelon form of the matrix:

1. We substract to row 2, two times the row 1.

We substract to row 3, three times the row 1.

We substract to row 4, four times the row 1 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&-4&-4&0&-12&-8\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]$

2. We multiply the second row of the preview step by -1/4. We obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&-8&-8&1&-26&-13\\0&-14&-14&-5&-32&-43\end{array}\right]$

We add to row 3, eight times the row 2.

We add to row 4, fourtheen times the row 2 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&-5&10&-155\end{array}\right]$

4. We add to row 4 of the preview step, five times the row 3 and obtain the matrix

$\left[\begin{array}{cccccc}1&5&4&3&9&18\\0&1&1&0&3&2\\0&0&0&1&-2&3\\0&0&0&0&0&-140\end{array}\right]$

Using backward substitution we have that

$0x_5=-140$ , then $0=-140$ and this is absurd. Then The system is inconsistent.

4 0

3 years ago

Construct line AB 11cm and construct a perpendicular P from line AB 6cm<br>

Arisa [49]

<h3>Step-by-step explanation:</h3>

let us drawn side AB11 cm

again let us drawn p from line AB 6 cm

8 0

3 years ago