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UNO [17]
2 years ago
13

Find the range for the domain {-3, 1,4.5} f(x) = 2x

Mathematics
1 answer:
exis [7]2 years ago
5 0

Answer:

Step-by-step explanation:

f(x) = 2x2

Range = {f(-3), f(1), f(4), f(5)} = {18, 2, 32, 50}

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Express 150 as:<br> a) A fraction of 350.<br> b) A percentage of 600.
NemiM [27]
A) 3/7 and B) 25%. Give me a like if I helped please :)
8 0
3 years ago
Read 2 more answers
What is the answer of:<br><img src="https://tex.z-dn.net/?f=2%20%5Cdiv%203%20%20%2B%20%20%5Csqrt%7B5%7D%20" id="TexFormula1" tit
pshichka [43]

Answer:

\frac{2  \: +  \: 3 \sqrt{5} }{3}

Step-by-step explanation:

\frac{2}{3}  +  \sqrt{5}  =

= \frac{2}{3}  + ( \sqrt{5}   \times  \frac{3}{3} )

= \frac{2}{3}  +  \frac{3 \sqrt{5} }{3}

=  \frac{2  \: +  \: 3 \sqrt{5} }{3}

4 0
2 years ago
WHat is the y- intercept of the quadratic function f(x)=(x-6)(x-2)?
aleksandrvk [35]
I think it's (0, -12)
7 0
2 years ago
Read 2 more answers
The Columbia Tower in Seattle is 954 feet tall. The Seafirst Tower is T feet tall and d feet away from the Colombia Tower. Find
Blababa [14]
You have to include a drawing that relates the distace between de towers and some angles.

I will use one that gives the angle from the base of Seafirst Tower to the top of Columbia tower as 53 degress.

This lets you calculate the distance between the towers, d, as

tan(53) = 954 / d => d = 954 / tan(53) = 718.89ft

The same drawing gives the angle from the the base of the Columbtia tower to the top of the Seafirst Tower as 27 degrees.

Tnen, tan(27) = height / d => height = d*tan(27) = 718.89*tan(27) = 366.29 ft

Answer: 366.29 ft


6 0
3 years ago
Rewrite this percent as a decimal:<br> 80%
ella [17]

Answer:

.80

or

0.80

Step-by-step explanation:

80 is out of 100, which is other words is .80 or 0.80

6 0
3 years ago
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