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mafiozo [28]
3 years ago
15

Which ordered pairs lie on the graph of the exponential equation f(x)=128(0.5)^x?

Mathematics
1 answer:
Shalnov [3]3 years ago
4 0
The answers are B C and D.
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tyreee bought a collection comic book for 49.62 last year.this year he would sold it for 52.10 find the percent of change.
wlad13 [49]

Answer:

The percentage increased by approximately 5%.

Step-by-step explanation:

52.10 - 49.62 = 2.48

2.48/49.62 x 100 = 4.998%

The percentage increase in the price is approximately 5%. Hope this helps! :)

3 0
3 years ago
HELP!!!!!!!!! ASAP!!!!!!!!!!
harkovskaia [24]

Answer:

45 degrees

Step-by-step explanation:

Angle c is 90 degrees

and angle b and a have the same number of degrees

180-90=90

90 divided by 2 is

45

5 0
3 years ago
Uy Islari
Andru [333]

Answer:

209.43  \:  \: {units}^{3}

Step-by-step explanation:

v = \pi {r}^{2}  \frac{h}{3}  \\  = \pi \times  {5}^{2}  \times  \frac{8}{3}  \\  = 209.439

7 0
3 years ago
10 POINTS! Please help me on the attached file!
tester [92]
Given:
Big figure = 20 ft
Small figure = 7 ft

Take note: In finding the scale factor, we must make sure that the measurements of both figures are the same sides or line.

20 feet / 7 feet = 2.86 scale factor.

This means that the big figure is 2.86 times bigger than the small figure.

If the arrow had been pointed from the small figure to the big figure.
7 feet / 20 feet = 0.35 scale factor.

This means that the small figure is only 0.35 of the big figure.

Both are scale factors but in different perspectives.
5 0
3 years ago
Trigonometry question help ,?? (15 points)
Taya2010 [7]
SOH CAH TOA
This is the acronym for all trigonometric ratios. 
Sin. = opposite/hypotenuse
Cos. = adjacent/ hypotenuse
Tan. = opposite/ adjacent.

In this picture the OPPOSITE leg and the HYPOTENUSE is given to us. With this information we can apply the "TOA" ratio.

Sin. R = opposite/hypotenuse
Sin. R = 3/4 or 0.75
Use a calculator or table to find 0.75 in the sin. column.
The final answer should be 49.
Sin. 49 = 0.7547
5 0
4 years ago
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