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NemiM [27]
2 years ago
10

The population of Mexico has been increasing at an annual rate of 1.7% . If the population was 100,350,000 in the year 2000, pre

dict its population in 2015. Round to the nearest whole number
Mathematics
2 answers:
damaskus [11]2 years ago
6 0
2015-2000=15 years P=100,350,000×(1+0.017)^(15) P=129,220,575.43
Kryger [21]2 years ago
6 0

Answer:

12,92,20,575.43

Step-by-step explanation:

Given that the population of Mexico has been increasing at an annual rate of 1.7%

Initial population = 100,350,000

i.e. 2000 is the year zero.

IN 2015, t = no of years from 2000 = 15

To find out population in 2015,

we find out P(15)

P(15) =100350000(1+0.017)^{15} \\=12,92,20,575.43

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MrRa [10]

The correct comparison for Weeks 5-8 is higher than Week 1-4, hence, the job satisfaction for Week 5-8 is 17% higher.

<u>Job Satisfaction Score</u> :

  • Week 1 = 3.50
  • Week 2 = 3.40
  • Week 3 = 3.30
  • Week 4 = 3.60
  • Week 5 = 4.20
  • Week 6 = 4.00
  • Week 7 = 4.10
  • Week 8 = 3.90

<u>Job Satisfaction for week 1 - 4</u> :

  • Week 1 + Week 2 + Week 3 + Week 4
  • (3.50 + 3.40 + 3.30 + 3.60) = 13.80

<u>Job Satisfaction for Week 5 - 8</u> :

  • Week 5 + Week 6 + Week 7 + Week 8
  • (4.20 + 4.00 + 4.10 + 3.90) = 16.20

<u>Difference</u><u> between the two categories</u> :

[(Week 5 - 8) - (Week 1-4)] / Week 1-4] × 100%

(16.20 - 13.80) / 13.80 × 100%

(2.4 / 13.80) × 100%

0.1739 × 100%

= 17.39%

Therefore, the job satisfaction for Week 5 - 8 is about 17% higher than Week 1 - 4

Learn more :brainly.com/question/13218948

8 0
2 years ago
A similarity ratio is the ratio of the lengths
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Similarity ratio is a ratio of two figures having the same side.

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3 years ago
there are 6 pure spectral color : red,orange,yellow, green,blue, and violet. some animals cannot see orange or red. what fractio
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8 0
3 years ago
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

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3 years ago
How to find solution to system of equations using substitution?
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Well u need to give me the equation and the substitutions for the variables then I can solve it
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