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2 years ago

What is the solution to the system of 4x-3y=1 and y+2x=3?

2 answers:

4 0

Use substitution, so subtract 2x from both sides of the second equation, leaving y by itself, so y=3-2x, or -2x+3. Then you have these two equations, y=-2x+3 and 4x-3y=1. Substitute -2x+3 for the y, giving the equation 4x-3(-2x+3) =1. Then you distribute and get 4x+6x-9=1. Combine like terms, and you're left wide 10x-9=1. Add nine, and you get 10x=10, so x=1

Svetradugi [14.3K]2 years ago

3 0

By any chance will it be (1,1)

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Question 4 options: Find the mean and standard deviation for a binomial distribution with 680 trials and a probability of succes

lys-0071 [83]

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Mean for a binomial distribution = 374

Standard deviation for a binomial distribution = 12.97

Step-by-step explanation:

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$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

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