What is the solution to the system of 4x-3y=1 and y+2x=3?

2 answers:

4 0

Use substitution, so subtract 2x from both sides of the second equation, leaving y by itself, so y=3-2x, or -2x+3. Then you have these two equations, y=-2x+3 and 4x-3y=1. Substitute -2x+3 for the y, giving the equation 4x-3(-2x+3) =1. Then you distribute and get 4x+6x-9=1. Combine like terms, and you're left wide 10x-9=1. Add nine, and you get 10x=10, so x=1

Svetradugi [14.3K]3 years ago

3 0

By any chance will it be (1,1)

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How much did you invest if you earned $131.60 in interest at a rate of 4% for seven years?

Ket [755]

The amount invested is $ 470

<h3><u>Solution:</u></h3>

Given that , we have earned $131.60 as simple interest for an amount deposit at the rate of 4% for seven years.

We have to find the amount invested. That is, we need to find the principal sum

Let us use the simple interest formula

<em><u>The simple interest is given as:</u></em>

$\text { Simple interest }=\frac{p r i n c i p a l \times \text {rate of interest } \times \text {number of years}}{100}$

Here, simple interest = $ 131.60

Rate of interest = 4 %

Number of years = 7

principal = ?

Substituting the values in formula, we get

$\begin{array}{l}{131.6=\frac{\text { principal } \times 4 \times 7}{100}} \\\\ {131.6 \times 100=\text { principal } \times 4 \times 7} \\\\ {13160=\text {principal } \times 28} \\\\ {\text {Principal }=470}\end{array}$