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3 years ago

What is the solution to the system of 4x-3y=1 and y+2x=3?

2 answers:

4 0

Use substitution, so subtract 2x from both sides of the second equation, leaving y by itself, so y=3-2x, or -2x+3. Then you have these two equations, y=-2x+3 and 4x-3y=1. Substitute -2x+3 for the y, giving the equation 4x-3(-2x+3) =1. Then you distribute and get 4x+6x-9=1. Combine like terms, and you're left wide 10x-9=1. Add nine, and you get 10x=10, so x=1

Svetradugi [14.3K]3 years ago

3 0

By any chance will it be (1,1)

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Step-by-step explanation:

We want to evaluate;

$\sec960\degree$

We use the reciprocals of trigonometric ratios to obtain;

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This implies that;

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$\sec960\degree=\frac{1}{-\frac{1}{2}}$

$\sec960\degree=-2$

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