Answer:
C. (4,7), (-7, -4), (6, 8), (-7, 6)
Step-by-step explanation:
There are no repeating numbers. For example, in answer A, 8 is repeated, (8, -1) and (8, 7)
Hope that helped! If you have any questions, just ask!
Answer:
Step-by-step explanation:
ASTC (I use a sentence to memorize: All Students Take Calculus):
Q1 - All functions are positive
Q2 - Sine is positive (Cosecant is positive as well) (all others negative)
Q3 - Tangent is positive (Cotangent is positive as well) (all others negative)
Q4 - Cosine is positive (Secant is positive as well) (all others negative)
Applying ASTC:
Secant is negative, so it can't be in quadrant 1, and quadrant 4.
Quadrant 2 - Sine and Quadrant 3 - Tangent are left.
Cosecant is positive so it can't be in quadrant 3.
Therefore, angle x is in Quadrant 2 or QII
Secant is hypotenuse / adjacent
5 = hypotenuse (hypotenuse is never a negative number)
-2 = adjacent
use pythagorean theorem to solve for opposite (bc tan = opp / adj)
tanx =
103 ft^2
take 3 and 5 and multiply it by 30
3*30=90
5.5*30=165
then divide them both by 12 to convert inches to feet
90÷12=7.5
165÷12=13.75
then multiply both dividends together
7.5*13.75=103.125
then round to the nearest whole number
103
For part a: you just need to find how far the vertex has been moved from the origin, or the point (0,0). As the vertex is at the point (2,-3), it has been translated right 2 horizontally and down 3 vertically.
For part b: you use the info found in part a to create the equation in the form of y=A(x-h)^2+k. In this case, A =1, so you can ignore it. The h value is the horizontal distance the vertex has been moved. Since it has been moved right 2, this part of the equation would be (x-2). I know it seems like it should be plus 2, but values in parentheses come out opposite. For the k value, find the vertical shift, which is down3, or -3.
Now that you have h and k, substitute them back into the equation.
Your final answer for part b is: y=(x-2)^2 -3.