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murzikaleks [220]
2 years ago
9

A parking meter contains nickels and quarters worth $7.70. There are 54 coins in all. Find how many of each there are.

Mathematics
1 answer:
OleMash [197]2 years ago
8 0

Let's assume there is n number of nickels coin and q number of quaters coin.

Given that there are 54 coins in total. So, sum of n and q must be equal to 54.

So, n + q =54.

Hence, q = 54 - n ...(1)

Now 1 nickel is worth of $0.01 nickel. So, n nickel will woth of 0.01n.

Similarly q quarters will worth of 0.25q.

Given that a parking meter contains nickels and quarters worth $7.70. So, sum of 0.01n and 0.25q will be equal to 7.70. Therefore,

0.01n + 0.25q = 7.70

From equation (1) we can plug in q=54-n in the above equation. So,

0.01n + 0.25 (54-n) = 7.70

0.01n + 13.5 -0.25n = 7.70

-0.24n + 13.5 = 7.70

-0.24n = 7.70 - 13.5

-0.24n = -5.8

\frac{-0.24n}{-0.24} =\frac{-5.8}{-0.24}

So, n= 24.167

Hence, n= 24 ( rounded to nearest integer).

Next step is to plug in n=24 in equation (1). So,

q = 54 - 24 = 30.

Hence, there will be 24 nickel and 30 quarter.

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Which situation is best represented by the equation? 35p + 129.50 = 479.50
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4°

Step-by-step explanation:

Since it is said that the angles are corresponding angles so we know that corresponding angles are equal then,

<1 = <2

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5 0
3 years ago
How many multiples of 4 are there in {n; 37&lt; n &lt;1001}?
s2008m [1.1K]
Let's begin by listing the first few multiples of 4:  4, 8, 12, 16, 20, 24, 28, 32, 36, 38, 40, 44.  So, between 1 and 37 there are 9 such multiples:  {4, 8, 12, 16, 20, 24, 28, 32, 36}.  Note that 4 divided into 36 is 9.

Let's experiment by modifying the given problem a bit, for the purpose of discovering any pattern that may exist:

<span>How many multiples of 4 are there in {n; 37< n <101}?  We could list and then count them:  {40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100}; there are 16 such multiples in that particular interval.  Try subtracting 40 from 100; we get 60.  Dividing 60 by 4, we get 15, which is 1 less than 16.  So it seems that if we subtract 40 from 1000 and divide the result by 4, and then add 1, we get the number of multiples of 4 between 37 and 1001:

1000
   -40
-------
 960

Dividing this by 4, we get 240.  Adding 1, we get 241.

Finally, subtract 9 from 241:  We get 232.

There are 232 multiples of 4 between 37 and 1001.

Can you think of a more straightforward method of determining this number? </span>

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3 years ago
Answer please and explain some of them!
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The first one is < because if you have 5 part of 7, you have more parts than if you have 4 parts of 7, but it’s negative so it’s the opposite
8 0
3 years ago
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