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erastova [34]
4 years ago
8

How do i find the product

Mathematics
1 answer:
Mekhanik [1.2K]4 years ago
8 0
I believe that the answer is <span><span>2<span>m2</span></span>+<span><span><span>−1</span>4</span>m</span></span>+<span>7<span>4 </span></span>
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An arfican elephant weighs 6 tons what is the weight of the elephant in pounds? 2000 pounds = 1 ton
grin007 [14]
The answer would be 12,000 pounds. simply multiply 2,000 x 6 = 12,000.
7 0
3 years ago
What is the GCF of 12x3 - 9x2
Oksanka [162]

Answer:

I would probably say 4

Step-by-step explanation:

6 0
4 years ago
-13 is 4 less than a number n
AURORKA [14]

n - 4 = -13

or

-13 = n - 4


hope that helps

7 0
3 years ago
Solve the system of equations:x + 3y - z = -4 2x - y + 2z = 13 3x - 2y - z = -9
tatiyna

Answer:

The solution to the system of equations is

\begin{gathered} x=\frac{179}{13} \\  \\ y=-\frac{279}{39} \\  \\ z=-\frac{48}{13} \end{gathered}

Explanation:

Giving the system of equations:

\begin{gathered} x+3y-z=-4\ldots\ldots\ldots\ldots\ldots\ldots..........\ldots\ldots\ldots\ldots.\ldots\text{.}\mathrm{}(1) \\ 2x-y+2z=13\ldots\ldots...\ldots\ldots\ldots\ldots..\ldots..\ldots\ldots\ldots\ldots\ldots.(2) \\ 3x-2y-z=-9\ldots\ldots\ldots.\ldots\ldots\ldots\ldots....\ldots\ldots.\ldots\ldots\ldots\text{.}\mathrm{}(3) \end{gathered}

To solve this, we need to first of all eliminate one variable from any two of the equations.

Subtracting (2) from twice of (1), we have:

5y-4z=-21\ldots\ldots\ldots\ldots\ldots.\ldots.\ldots..\ldots..\ldots\ldots.\ldots..\ldots\text{...}\mathrm{}(4)

Subtracting (3) from 3 times (1), we have

3y-5z=-3\ldots\ldots...\ldots\ldots..\ldots\ldots\ldots\ldots\ldots.\ldots\ldots\ldots\ldots\ldots..\ldots\ldots(5)

From (4) and (5), we can solve for y and z.

Subtract 5 times (5) from 3 times (4)

\begin{gathered} 13z=-48 \\  \\ z=-\frac{48}{13} \end{gathered}

Using the value of z obtained in (5), we have

\begin{gathered} 3y-5(-\frac{48}{13})=-3 \\  \\ 3y+\frac{240}{13}=-3 \\  \\ 3y=-3-\frac{240}{13} \\  \\ 3y=-\frac{279}{13} \\  \\ y=-\frac{279}{39} \end{gathered}

Using the values obtained for y and z in (1), we have

\begin{gathered} x+3(-\frac{279}{39})-(-\frac{48}{13})=-4 \\  \\ x-\frac{279}{13}+\frac{48}{13}=-4 \\  \\ x-\frac{231}{13}=-4 \\  \\ x=-4+\frac{231}{13} \\  \\ x=\frac{179}{13} \end{gathered}

8 0
1 year ago
Help needed plse
kirza4 [7]
Life probably stayed the same because a farm is big and usually cities are big too. The difference is that a city is VERY loud. especially at night. A farm is very quiet.
6 0
3 years ago
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