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Liono4ka [1.6K]
2 years ago
8

From 3 cups of the secret recipe, 5 pies can be made.

Mathematics
1 answer:
Vsevolod [243]2 years ago
3 0

3/5=x/20

x = 3/5 * 20

x=12 cups

So, C is the answer

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Which expression represents the products of 5 and the sum of b and 4
AnnZ [28]

Answer:

5,b+4

Step-by-step explanation:

8 0
3 years ago
Original price 195 sale price 136.50 what is percent discount
GREYUIT [131]

Answer:

30%.

First find the difference between the two prices.

195 - 136.5 = 58.5

Next find percent of difference over original cost.

58.5/195 = 0.30

The percent discount is 30%.

To check:

195 * 0.70 = 136.5     <---------- CORRECT.

8 0
3 years ago
Read 2 more answers
Helpppppppppppppppppppppppp
Vaselesa [24]
The first thing to is factor the denominator of the rational function:
x^{2} -2x-3 to do this we'll need to find two number whose product is -3 and its sum is -2; those numbers are 1 and -3, so:
x^{2} -2x-3=(x+1)(x-3)
Now we can rewrite our rational function as follows:
f(x)= \frac{x-3}{(x+1)(x-3)}
Notice that we have a common factor (x-3) in both numerator and denominator; therefore we can cancel them:
f(x)= \frac{1}{x+1}

Taking all the above into consideration we realize that x=3 is a removable discontinuity; the correct answer is the first one: there is a hole in x=3 and asymptote  at x=-1.

4 0
3 years ago
Suppose you are given either a fair dice or an unfair dice (6-sided). You have no basis for considering either dice more likely
hoa [83]

Answer: Our required probability is 0.83.

Step-by-step explanation:

Since we have given that

Number of dices = 2

Number of fair dice = 1

Probability of getting a fair dice P(E₁) = \dfrac{1}{2}

Number of unfair dice = 1

Probability of getting a unfair dice  P(E₂) = \dfrac{1}{2}

Probability of getting a 3 for the fair dice P(A|E₁)= \dfrac{1}{6}

Probability of getting a 3 for the unfair dice P(A|E₂) = \dfrac{1}{3}

So, we need to find the probability that the die he rolled is fair given that the outcome is 3.

So, we will use "Bayes theorem":

P(E_1|A)=\dfrac{P(E_1)P(A|E_1)}{P(E_1)P(A|E_1)+P(E_2)P(A|E_2)}\\\\(E_1|A)=\dfrac{0.5\times 0.16}{0.5\times 0.16+0.5\times 0.34}\\\\P(E_1|A)=0.83

Hence, our required probability is 0.83.

8 0
3 years ago
Hi can anyone help me with these 3 questions would really appreciate it thanks
Virty [35]

Answer:

1) 8

Step-by-step explanation:

3+2 is 5

4^2 is 16

16×5=80

2×5=10

80÷10=8

7 0
3 years ago
Read 2 more answers
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