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nekit [7.7K]
3 years ago
7

What weight pencil is recommended for darkening lines and for lettering? *

Computers and Technology
2 answers:
Olenka [21]3 years ago
7 0

Answer: darkened

Explanation: darkened

dlinn [17]3 years ago
3 0

Answer:

While the softer B pencils are generally considered the best for shading, there's no reason to discount the harder H pencils. The HB and H are good choices for fine, light, even shading. However, they too have drawbacks. Pencil grades from HB through H, 2H to 5H get progressively harder and are easier to keep sharp.

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yes go to settings then apps

Explanation:

that's how I did mines

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Which of the following actions is most likely to be effective in reducing the digital divide at a local level? A Creating an app
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Which of the following is not a valid SQL command? (Points : 2) UPDATE acctmanager SET amedate = SYSDATE WHERE amid = 'J500';
Volgvan

Answer:

UPDATE acctmanager WHERE amid = 'J500';

Explanation:

The statement written above is not valid SQL statement because there is no SET after UPDATE. Update is always used with SET.If you are updating something then you need to specify the value with which that value should be replaced.

UPDATE acctmanager SET amname = UPPER(amname);

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Which of the following is normally mutually exclusive<br> Read only files<br> Printer<br> WIFI
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2 years ago
Integers and booleans. Write a program RightTriangle that takes three int command-line arguments and determines whether they con
icang [17]

Answer:

<em>The programming language is not stated;</em>

<em>I'll answer using C++</em>

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

int side1, side2, side3;

cout<<"Enter the three sides of the triangle: "<<endl;

cin>>side1>>side2>>side3;

if(side1<=0 || side2 <= 0 || side3 <= 0) {

 cout<<"Invalid Inputs";

}

else {

 if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else {

  cout<<"Not Right Angled";

 }

}

return 0;

}

Explanation:

The following line declares the three variables

int side1, side2, side3;

The next line prompts user for input of the three sides

cout<<"Enter the three sides of the triangle: "<<endl;

The next line gets user input

cin>>side1>>side2>>side3;

The following if condition checks if any of user input is negative or 0

<em> if(side1<=0 || side2 <= 0 || side3 <= 0) { </em>

<em>  cout<<"Invalid Inputs"; </em>

<em> } </em>

If otherwise

else {

The following if condition assumes that side1 is the largest and test using Pythagoras Theorem

<em>if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side2 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side3 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

If none of the above conditions is true, then the triangle is not a right angles triangle

<em>  else { </em>

<em>   cout<<"Not Right Angled"; </em>

<em>  } </em>

}

return 0;

Download cpp
4 0
3 years ago
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