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3 years ago

What weight pencil is recommended for darkening lines and for lettering? *

Computers and Technology

2 answers:

Olenka [21]3 years ago

7 0

Answer: darkened

Explanation: darkened

dlinn [17]3 years ago

3 0

Answer:

While the softer B pencils are generally considered the best for shading, there's no reason to discount the harder H pencils. The HB and H are good choices for fine, light, even shading. However, they too have drawbacks. Pencil grades from HB through H, 2H to 5H get progressively harder and are easier to keep sharp.

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If the three operations were combined, O(logN) + O(N) * O(logN) + 1, the overall algorithm cost would be:________

KiRa [710]

Answer:

D. O(NlogN)

Explanation:

The computation of the overall algorithm cost is as follows:

Given that

O(logN) + O(N) × O(logN) + 1

In the case of complexity we considered the high order that dominates the other terms

Thus, that term would be

O(N) × O(logN)

It could be rewrite as

O(NlogN)

Hence, the correct option is D.

All the other options are wrong

3 0

3 years ago

All of the following are incentives proprietary schools use to attract a student except

IRISSAK [1]

Idk what the answer choices are

4 0

3 years ago

Read 2 more answers

Part 1 of 4 parts for this set of problems: Given an 4777 byte IP datagram (including IP header and IP data, no options) which i

LekaFEV [45]

Answer:

Fragment 1: size (1332), offset value (0), flag (1)

Fragment 2: size (1332), offset value (164), flag (1)

Fragment 3: size (1332), offset value (328), flag (1)

Fragment 4: size (781), offset value (492), flag (1)

Explanation:

The maximum = 1333 B

the datagram contains a header of 20 bytes and a payload of 8 bits( that is 1 byte)

The data allowed = 1333 - 20 - 1 = 1312 B

The segment also has a header of 20 bytes

the data size = 4777 -20 = 4757 B

Therefore, the total datagram = 4757 / 1312 = 4

6 0

2 years ago

Create a conditional expression that evaluates to string "negative" if userVal is less than 0, and "non-negative" otherwise. Ex:

ArbitrLikvidat [17]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

System.out.print("Enter a number: ");

int userVal = input.nextInt();

String aString;

if(userVal < 0)

aString = "negative";

else

aString = "non-negative";

System.out.println(aString);

}

Explanation:

Ask the user to enter a number and set it to userVal

Check the value of userVal. If it is smaller than 0, set the string as "negative". If it is not, set it as "non-negative"

Print the string

8 0

3 years ago

FREE BRAINLIEST!!!

Nastasia [14]

Answer:

Explanation:

4 0

3 years ago

Read 2 more answers