Answer:
, 
Explanation:
The ideal efficiency of the Diesel cycle is given by this expression:
![\eta_{th} = \left\{1 - \frac{1}{r^{k-1}} \cdot \left[\frac{r_{c}^{k}-1}{k\cdot (r_{c}-1)} \right]\right\}\times 100\%](https://tex.z-dn.net/?f=%5Ceta_%7Bth%7D%20%3D%20%5Cleft%5C%7B1%20-%20%5Cfrac%7B1%7D%7Br%5E%7Bk-1%7D%7D%20%5Ccdot%20%5Cleft%5B%5Cfrac%7Br_%7Bc%7D%5E%7Bk%7D-1%7D%7Bk%5Ccdot%20%28r_%7Bc%7D-1%29%7D%20%5Cright%5D%5Cright%5C%7D%5Ctimes%20100%5C%25)
Where
and
are the compression and cutoff ratios, respectively.
![\eta_{th} = \left\{1-\frac{1}{18^{0.4}}\cdot \left[\frac{1.5^{1.4}-1}{1.4\cdot (1.5-1)} \right] \right\}\times 100\%](https://tex.z-dn.net/?f=%5Ceta_%7Bth%7D%20%3D%20%5Cleft%5C%7B1-%5Cfrac%7B1%7D%7B18%5E%7B0.4%7D%7D%5Ccdot%20%5Cleft%5B%5Cfrac%7B1.5%5E%7B1.4%7D-1%7D%7B1.4%5Ccdot%20%281.5-1%29%7D%20%5Cright%5D%20%5Cright%5C%7D%5Ctimes%20100%5C%25)

The heat addition to the cycle is:



The temperature at state 2 is:



And the temperature at state 3 is:



Answer:
a) True
Explanation:
Cavitation in a pump occurs when the pressure of the liquid inside the pump suction is less than the vapour pressure at the suction. And also when the pump discharge pressure is extremely high.
Therefore cavitation in the pump assemblies can be avoided by decreasing the tank pressure because discharge cavitation takes place when the pressure at the pump discharge is extremely high. High pressure at the discharge end of the pump prevents the water from flowing easily out, thereby recirculating the water within the pump which causes cavitation. So when the tank pressure is low, the pump discharge pressure will be low thus avoiding cavitation.
Answer:
105 km
Explanation:
The motorist was going 30 km/hr, and it took 3 hours 30 minutes. That's 3.5 hours. 3.5×30=105
Answer:
The air heats up when being compressed and transefers heat to the barrel.
Explanation:
When a gas is compressed it raises in temperature. Assuming that the compression happens fast and is done before a significant amount of heat can be transferred to the barrel, we could say it is an adiabatic compression. This isn't exactly true, it is an approximation.
In an adiabatic transformation:

For air k = 1.4
SO





SInce it is compressing, the fraction P1/P0 will always be greater than one, and raised to a positive fraction it will always yield a number greater than one, so the final temperature will be greater than the initial temperature.
After it was compressed the hot air will exchange heat with the barrel heating it up.