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Nitella [24]
3 years ago
14

Most schools use a learning management system (LMS) in order to make daily tasks easier, like taking attendance, entering grades

, and: communicating with students and parents. Changing data into a different form, in order to prevent unauthorized access. Ensuring that regulations and standards are being met. Sorting through large amounts of data.
Engineering
1 answer:
Sauron [17]3 years ago
3 0

Answer:

<u> like taking attendance, entering grades, and: communicating with students and parents.</u>

<u>Explanation:</u>

Indeed, the learning management system (LMS) is a <em>multipurpose software application</em> that allows an organization to record, analyze, and distribute information at flexibility.  For example, a school can use this software to take attendance, enter student grades, and can facilitate communication with students and parents.

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A cold air-standard Diesel cycle has a compression ratio of 18 and a cutoff ratio of 1.5. Determine the maximum temperature of t
Debora [2.8K]

Answer:

\dot Q_{in} = 228.659\,kW, T_{3} = 1573.662\,K\,(1300.512\,^{\textdegree}C)

Explanation:

The ideal efficiency of the Diesel cycle is given by this expression:

\eta_{th} = \left\{1 - \frac{1}{r^{k-1}} \cdot \left[\frac{r_{c}^{k}-1}{k\cdot (r_{c}-1)} \right]\right\}\times 100\%

Where r and r_{c} are the compression and cutoff ratios, respectively.

\eta_{th} = \left\{1-\frac{1}{18^{0.4}}\cdot \left[\frac{1.5^{1.4}-1}{1.4\cdot (1.5-1)} \right] \right\}\times 100\%

\eta_{th} = 65.648\,\%

The heat addition to the cycle is:

\dot Q_{in} = \frac{\dot W}{\eta_{th}}

\dot Q_{in} = \frac{150\,kW}{0.656}

\dot Q_{in} = 228.659\,kW

The temperature at state 2 is:

T_{2} = T_{1} \cdot r^{k-1}

T_{2} = (330.15\,K)\cdot 18^{0.4}

T_{2} = 1049.108\,K\,(775.958\,^{\textdegree}C)

And the temperature at state 3 is:

T_{3} = T_{2}\cdot r_{c}

T_{3} = (1.5)\cdot (1049.108\,K)

T_{3} = 1573.662\,K\,(1300.512\,^{\textdegree}C)

4 0
3 years ago
What is the eye an example of?<br><br><br><br> sense organ<br> stimulus <br> a relay neuron
Vikentia [17]

sens organ is the eye example

3 0
3 years ago
Cavitation in pump assemblies can be avoided by decreasing tank pressure. a)-True b)-False
IgorLugansk [536]

Answer:

a) True

Explanation:

Cavitation in a pump occurs when the pressure of the liquid inside the pump suction is less than the vapour pressure at the suction. And also when the pump discharge pressure is extremely high.

Therefore cavitation in the pump assemblies can be avoided by decreasing the tank pressure because discharge cavitation takes place when the pressure at the pump discharge is extremely high.  High pressure at the discharge end of the pump prevents the water from flowing easily out, thereby recirculating the water within the pump which causes cavitation. So when the tank pressure is low, the pump discharge pressure will be low thus avoiding cavitation.

7 0
4 years ago
If a motorist moves with a speed of 30 km/hr, and covers the distance from place A to place B
Sergio039 [100]

Answer:

105 km

Explanation:

The motorist was going 30 km/hr, and it took 3 hours 30 minutes. That's 3.5 hours. 3.5×30=105

5 0
4 years ago
The barrel of a bicycle tire pump becomes quite warm during use. Explain the mechanisms responsible for the temperature increase
Alexeev081 [22]

Answer:

The air heats up when being compressed and transefers heat to the barrel.

Explanation:

When a gas is compressed it raises in temperature. Assuming that the compression happens fast and is done before a significant amount of heat can be transferred to the barrel, we could say it is an adiabatic compression. This isn't exactly true, it is an approximation.

In an adiabatic transformation:

P^{1-k} * T^k = constant

For air k = 1.4

SO

P0^{-0.4} * T0^{1.4} = P1^{-0.4} * T1^{1.4}

T1^{1.4} = \frac{P1^{0.4} * T0^{1.4}}{P0^{0.4}}

T1^{1.4} = \frac{P1}{P0}^{0.4} * T0^{1.4}

T1 = T0 * \frac{P1}{P0}^{0.4/1.4}

T1 = T0 * \frac{P1}{P0}^{0.28}

SInce it is compressing, the fraction P1/P0 will always be greater than one, and raised to a positive fraction it will always yield a number greater than one, so the final temperature will be greater than the initial temperature.

After it was compressed the hot air will exchange heat with the barrel heating it up.

5 0
3 years ago
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