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rosijanka [135]
1 year ago
9

Topic 4: Workers Rights Practice Worksheet Crossword Puzzle OSHA Provides Workers the Right to: Across _andmedicalre cords 6. In

formation about 7, A safe and & complain or request hazard 9. Participate in an OSHA andiinesses in your workplace from employer Down I. Know about 2. Be free from as provided in the OSHA standards 5, File a complaint with ー 2017
Engineering
1 answer:
ELEN [110]1 year ago
4 0

Workers Rights Practice Worksheet Crossword Puzzle OSHA Provides Workers the Right to

1- HAZARDOUS             (down)

2- RETALIATION             (down)

3- TRAINING                   (down)

4- EXPOSURE                (across)

5- OSHA                           (down)

6-

7- HEALTHFUL                (across)            

8- CORRRECTION          (across)

9- INSPECTION                (across)

<h3>What is workers right?</h3>

Workers' rights are not enumerated or given a single definition. According to the International Labor Organization (ILO), all ILO Members are obligated to uphold and respect certain "fundamental principles and rights at work," including:

Freedom of association, the effective recognition of the right to collective bargaining, the abolition of all forms of forced or compulsory labor, the end of child labor, the eradication of discrimination in employment and occupation, and the creation of a safe and healthy workplace are all guaranteed.

International labor conventions have been adopted in each of these areas, and the ILO oversees their implementation. Although these standards are important, they are not regarded as "fundamental" or "core" conventions because they deal with conditions of work, such as pay and hours.

Learn more about Workers' rights

brainly.com/question/14296409

#SPJ1

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You are working as an electrical technician. One day, out in the field, you need an inductor but cannot find one. Looking in you
telo118 [61]

Answer:

a) the inductance of the coil is 6 mH

b) the emf generated in the coil is 18 mV  

Explanation:

Given the data in the question;

N = 570 turns

diameter of tube d = 8.10 cm = 0.081 m

length of the wire-wrapped portion l =  35.0 cm = 0.35 m

a) the inductance of the coil (in mH)

inductance of solenoid

L = N²μA / l

A = πd²/4  

so

L = N²μ(πd²/4) / l

L = N²μ(πd²) / 4l

we know that μ = 4π × 10⁻⁷ TmA⁻¹

we substitute

L = [(570)² × 4π × 10⁻⁷× ( π × (0.081)² )] / 4(0.35)

L =  0.00841549 / 1.4

L = 6 × 10⁻³ H    

L = 6 × 10⁻³ × 1000 mH

L = 6 mH

Therefore, the inductance of the coil is 6 mH

b)

Emf ( ∈ ) = L di/dt

given that; di/dt = 3.00 A/sec

{∴ di = 3 - 0 = 3 and dt = 1 sec}

Emf ( ∈ ) = L di/dt

we substitute

⇒ 6 × 10⁻³ ( 3/1 )

= 18 × 10⁻³ V

= 18 × 10⁻³ × 1000

= 18 mV  

Therefore, the emf generated in the coil is 18 mV  

7 0
3 years ago
Thermal conductivity of AISI 316 Stainless Steel at 90ºC is 14.54 W/m K. Convert this value to IP system.
abruzzese [7]

Answer:

the value of conductivity in IP is 8.406\dfrac{Btu}{ft.hr.F}

Explanation:

Given that

Thermal conductivity K=14.54 W/m.K

This above given conductivity is in SI unit.

     SI unit                                           IP unit              Conversion factor

    m                                                      ft                      0.3048

   W                                                       Btu/hr               0.293          

 

The unit of conductivity in IP is Btu./ft.hr.F.

Now convert into IP divided by 1.73 factor.

0.57\dfrac{Btu}{ft.hr.F}=1 \dfrac{W}{m.K}

So

0.57\times 14.54\dfrac{Btu}{ft.hr.F}=14.54 \dfrac{W}{m.K}

8.406\dfrac{Btu}{ft.hr.F}=14.54 \dfrac{W}{m.K}

So the value of conductivity in IP is 8.406\dfrac{Btu}{ft.hr.F}

 

7 0
3 years ago
A steel rotating-beam test specimen has an ultimate strength Sut of 1600 MPa. Estimate the life (N) of the specimen if it is tes
ziro4ka [17]

Answer:

the life (N) of the specimen is 46400 cycles

Explanation:

given data

ultimate strength Su = 1600 MPa

stress amplitude σa = 900 MPa

to find out

life (N) of the specimen

solution

we first calculate the endurance limit of specimen Se i.e

Se = 0.5× Su   .............1

Se = 0.5 × 1600

Se = 800 Mpa

and we know

Se for steel is 700 Mpa for Su ≥ 1400 Mpa

so we take endurance limit Se is = 700 Mpa

and strength of friction f  = 0.77 for 232 ksi

because for Se 0.5 Su at 10^{6} cycle = (1600 × 0.145 ksi ) = 232

so here coefficient value (a) will be

a = \frac{(f*Su)^2}{Se}    

a = \frac{(0.77*1600)^2}{700}  

a = 2168.3 Mpa

so

coefficient value (b) will be

a = -\frac{1}{3}log\frac{(f*Su)}{Se}

b =  -\frac{1}{3}log\frac{(0.77*1600)}{700}

b = -0.0818

so no of cycle N is

N =  (\frac{ \sigma a}{a})^{1/b}

put here value

N =  (\frac{ 900}{2168.3})^{1/-0.0818}

N = 46400

the life (N) of the specimen is 46400 cycles

5 0
3 years ago
Tech a says that only a certain few people will find jobs in the automotive industry. Tech b says the automotive industry offers
finlep [7]

Answer: Tech B

Explanation:

From the question above, tech B saying the automotive industry offers numerous career choices is the correct answer. Pursuing a career in automotive industry is challenging and rewarding as one works with both vehicles and technology.

Examples of career choices in the automotive industry are car detailer, tire technician, car rental agent, auto mecahnic, vehicle inspector, auto electrician, auto engineer etc.

7 0
3 years ago
Read 2 more answers
Find the total amount of heat Q lost through a wall 10’ by 18’, with R value from q. 1. Inside temperature is 70°F while outside
myrzilka [38]

Answer:

1110831

Explanation:

7 0
3 years ago
Read 2 more answers
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