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vlada-n [284]
4 years ago
13

What are the steps you would take to find the area of

Mathematics
2 answers:
Lina20 [59]4 years ago
7 0

Answer:

A and C

Step-by-step explanation:

kodGreya [7K]4 years ago
3 0

Answer: Identify the shapes you will need to determine the area of the figure.

Calculate and add the areas of the unshaded triangle and two circles.

Step-by-step explanation:

You might be interested in
The one-time fling! Have you ever purchased an article of clothing (dress, sports jacket, etc.), worn the item once to a party,
rjkz [21]

Answer:

a)  0.2725

b)  0.7275

c)  0.8948

Step-by-step explanation:

This is a binomial distribution probability problem. The formula is:

P(x)=\frac{n!}{(n-x)!x!}p^{x}q^{n-x}

Where

n is the number of trials [here we are taking 8 person, so n = 8]

x is what we are looking for [in the problem]

p is the probability of success [ 15%, so p = 0.15

q is the probability of failure [q = 1-p = 0.85]

Now,

a)

We are looking for "no one" did fling, so x = 0

Let's put into formula and find out the probability:

P(x=0)=\frac{8!}{(8-0)!0!}(0.15)^{0}(0.85)^{8}\\P(x=0)=0.2725

So, the probability that no one has done a one-time fling is 0.2725

b)

Atleast 1 person means P(x ≥ 1).

This can be found by:

P(x ≥ 1) = 1 - P(x=0) = 1 - 0.2725 = 0.7275

THus, Probability that at least one person has done a one-time fling is 0.7275

c)

No more than 2 people means P (x≤2).

This is essentially

P ( x ≤ 2 ) = P(x=0) + P(x=1) + P(x=2)

P ( x = 0 ) is found in part (a), which is 0.2725

P (x = 1 ) and P(x=2) can be found using formula:

P(x=1)=\frac{8!}{(8-1)!1!}(0.15)^{1}(0.85)^{7}\\P(x=1)=0.3847

and

P(x=2)=\frac{8!}{(8-2)!2!}(0.15)^{2}(0.85)^{6}\\P(x=2)=0.2376

Thus,

P ( x ≤ 2 ) = P(x=0) + P(x=1) + P(x=2) = 0.2725 + 0.3847 + 0.2376 = 0.8948

8 0
3 years ago
Assume that you assign the following subjective probabilities for your final grade in your econometrics course (the standard GPA
rodikova [14]

Answer:

E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78

So then the best answer for this case would be:

C. 2.78

Step-by-step explanation:

For this case we have the following probabability distribution function given:

Score         P(X)

A= 4.0       0.2

B= 3.0       0.5

C= 2.0       0.2

D= 1.0        0.08

F= 0.0       0.02

______________

Total          1.00

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

If we use the definition of expected value given by:

E(X) = \sum_{i=1}^n X_i P(X_I)

And if we replace the values that we have we got:

E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78

So then the best answer for this case would be:

C. 2.78

3 0
3 years ago
Solve the equation <br> 2 ( a + 10) = 56
Hatshy [7]
Answer: a = 18

explanation:
2(a + 10) = 56 -> distribute the 2
2a + 20 = 56 -> subtract 20 from both sides
2a = 56 - 20
2a = 36 -> divide both sides by 2
a = 18
3 0
3 years ago
A set of three scores consists of the values 3, 7, and 2. Σ2(X – 3) =
siniylev [52]

Answer:

6

Step-by-step explanation:

\sum 2(X-3)=2(3-3)+2(7-3)+2(2-3)=0+8-2=6

5 0
2 years ago
A music teacher asked 23 students in the band how many hours they practiced playing their instrument each week. The results are
valkas [14]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

A music teacher asked 23 students in the band how many hours they practiced playing their instrument each week. The results are shown in the dot plot. Which statement best describes the data?

a. The data are skewed left, so most student's practice times are more than the mean practice time.

b. The data are skewed left, so most student's practice times are less than the mean practice time.

c. The data are skewed right, so most student's practice times are less than the mean practice time.

d. The data are skewed right, so most student's practice times are more than the mean practice time.

Answer:

The correct option is a.

The data are skewed left, so most student's practice times are more than the mean practice time.

Step-by-step explanation:

Refer to the attached box plot which shows number of hours the students spent on practice for playing their instrument each week.

When the data distribution is not symmetric around the mean then it is either skewed to right or skewed to left.

The given box plot is skewed to the left since the tail of the distribution on the left side is longer than the right side or in other words, most of the data is leaning to the right side of the curve.

Due to this, most student's practice times are more than the mean practice time.

A left skewed distribution is also known as negatively skewed distribution.

Therefore, we can conclude that the correct option is a.

a. The data are skewed left, so most student's practice times are more than the mean practice time.

4 0
3 years ago
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