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kvv77 [185]
2 years ago
15

Evaluate 8j -k+14 when j = 0.25 and k =1

Mathematics
2 answers:
Amiraneli [1.4K]2 years ago
7 0
Substitute
8(0.25) -1+14 = 15
bazaltina [42]2 years ago
3 0

Algebraic expression is the expression which contains variable with some mathematical operations without any equal to sign.

Given algebraic expression is 8j -k+14

Here the variables are j and k

First term is 8j which means 8 time j

j= 0.25 and k =1

Now plug in j=0.25 and k = 1 in the above algebraic expression, we get

8j -k+14 = 8(0.25) - 1 + 14

= 2 -1 +14

= 1 + 14

=15

So value of the given algebraic expression 8j -k+14 is 15

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Answer:

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

Step-by-step explanation:

Use the formula for the mean: sum of elements / number of elements

Let x represent her first exam score.

Her second exam score can be represented by x + 11, since it was 11 points better than her first.

Her third exam score can be represented by (x + 11) + 5, since it was 5 points better than her second.

Plug in all of these expressions into the mean formula. Plug in 87 as the mean, and plug in 3 as the number of elements (since there are 3 scores):

mean = sum of elements / number of elements

87 =  ( (x) + (x + 11) + (x + 11) + 5 ) / 3

Add like terms and solve for x:

87 = (3x + 27) / 3

261 = 3x + 27

234 = 3x

78 = x

So, her first score was a 78.

Find her second score by adding 11 to this:

78 + 11 = 89

Find her third score by adding 5 to the second score:

89 + 5 = 94

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

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3 years ago
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Answer:

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Step-by-step explanation:

Here, we use the principles of alternate angles, corresponding angles and vertically opposite angles to confirm which of the statements are true. Alternate angles are always equal, corresponding angles are equal, likewise vertically opposite angles.

From the given question, it was given that a is parallel to b. Thus, it can be observed and deduced that;

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and

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So that,

m∠2 = m∠7  

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