Answer:
Y
opportunity cost
Step-by-step explanation:
The Production Possibilities Curve, shows the maximum combinations of two goods a theoretical economy can produce with the current state of technology and given the available resources.
Any increase in the production of one commodity must be done at the expense of the other, the opportunity cost of the good increased is the number of unit of the other that we have to give up.
in this question the opportunity cost of producing 10 more unit of good X is the 5 units of good Y that was given up.
Answer:
Step-by-step explanation:
Let the rate at which the bacteria grow be represented by the exponential equation
P(t) = P0e^kt
P(t) is the population of the bacteria after time t
P0 is the initial population
k is the constant of variation
t is the time
If the initial Population is 160 bacteria's, them the equation becomes;
P(t) = 160e^kt
b) if After 5 hours there will be 800 bacteria, this means
at t = 5 p(t) = 800
Substitute and get k
800 = 160e^5k
800/160 = e^5k
5 = e^5k
Apply ln to both sides
Ln5 = lne^5k
ln5 = 5k
k = ln5/5
k = 0.3219
Next is to calculate the population after 7hrs i.e at t = 7
P(7) = 160e^0.3219(7)
P(7) = 160e^2.2532
P(7) = 160(9.5181)
P(7) = 1522.9
Hence the population after 7houra will be approximately 1523populations
c) To calculate the time it will take the population to reach 2790
When p(t) = 2790, t = ?
2790 = 160e^0.3219t
2790/160 = e^0.3219t
17.4375 = e^0.3219t
ln17.4375 = lne^0.3219t
2.8587 = 0.3219t
t = 2.8587/0.3219
t = 8.88 hrs
Hence it will take approximately 9hrs for the population to reach 2790
Answer:

Step-by-step explanation:
When you have two parallel lines, corresponding angles such as the values of

Then, they are equal, so solve for x.

I'm not good at graphing, but desmos.com is an online graphing calculator that works really well.
Answer:
Minimum value = 
- Set up the function in general form
- Determine the direction of the graph
- Calculate -b/2a
- Find the corresponding f(x) value
- Write your quadratic function in standard or vertex form
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