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Lady bird [3.3K]
3 years ago
6

3 erasers cost $4.41.

Mathematics
1 answer:
olasank [31]3 years ago
6 0
Y=1.47x

X is the number of erasers bought
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14. Solve: (a) 2y - 1/2 = -1/3 (b) 6 + 5 (a - 1) = 30
Strike441 [17]

A)2y - 1/2 = -1/3

2y=-1/3+1/2

FIND THE LCM TO MAKE THE FRACTIONS LIKE FRACTIONS

LCM OF 3 AND 2 IS 6

-1/3*2=-2/6

1/2*3=3/6

-2/6+3/6=1/6

2y=1/6

y=1/6 ÷ 2

TAKING THE RECIPROCAL,

RECIPROCAL OF 2 IS 1/2

y=1/6*1/2

y=1/12

B) 6 + 5 (a - 1) = 30

6+(5)*(a)+(5)*(−1)=30(Distribute)

6+5a+−5=30

(5a)+(6+−5)=30(Combine Like Terms)

5a+1=30

5a=30-1

5a=29

a=29/5

15.sum of three consecutive integers=48

let the numbers be x ,x+1,x+2

x+x+1+x+2==48

3x+3=48

3x=48-3

3x=45

x=45/3

x=15

x+1=15+1=16

x+2=15+2=17

the numbers are 15,16,17

​​  

7 0
3 years ago
Someone plz help meh
gogolik [260]

Answer:

<em>f( g ( - 2 ) ) = - 14 </em>

Step-by-step explanation:

f(x) = - 2x + 4

g(x) = 3x² - x - 5

f( g ( - 2 ) ) = ?

g( - 2 ) = 3( - 2 )² - ( - 2 ) - 5 = 12 + 2 - 5 = 9

f(9) = - 2 × 9 + 4 = - 14

<em>f( g ( - 2 ) ) = - 14</em>

7 0
2 years ago
Consider a circle centered at C(-2,-4). If the point P(1,-1) lies on the circle, then which of the following points also lies on
Aliun [14]

Answer:

Consider a circle centered at C(-2,-4). If the point P(1,-1) lies on the circle, then which of the following points also lies on the circle?

<h3>A. (-2, -√18)</h3>

B. (-2+√18, -4)

C. (√18, -4)

D. (-2, 4+√18)

Step-by-step explanation:

  • If the distance is greater than the radius, the point lies outside. If it's equal to the radius, the point lies on the circle. And if it's less than the radius, you guessed it right, the point will lie inside the circle.

hope it's help you

7 0
3 years ago
Find the x- and y- intercepts of parabola y=5x^2-16x+10
____ [38]

Y-INTERCEPT

y = 5x^2 - 16x + 10

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0

We need to use the quadratic formula

The quadratic formula helps us find what values of x make the equation = 0

Quadratic formula: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\

The x-intercepts are at:

(\frac{8 + \sqrt{14}}{5}, 0)\\(\frac{8 - \sqrt{14}}{5}, 0)

5 0
2 years ago
What number 1,2,3? Im a lil confused:/
max2010maxim [7]
Undo the X first...........
5 0
3 years ago
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