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3 years ago

6

How many repeating digits are in 0.536?

2 answers:

Shkiper50 [21]3 years ago

8 0

Answer:

4

Step-by-step explanation:

Makovka662 [10]3 years ago

8 0

Answer:

there are 3 repeating digits in 0.536 because there are 3 numbers behind the decimal.

Step-by-step explanation:

3

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A, B, and C are collinear points, where B is between A and C. Find x if AB = x, BC = x + 6, and AC = 24. Then find the measures

Alekssandra [29.7K]

Answer:

AB = 9, BC = 15

Step-by-step explanation:

Since, A, B, and C are collinear points, where B is between A and C. i. e. A - B - C

$\therefore AC = AB + BC\\\therefore 24 = x + x + 6\\\therefore 24 = 2x + 6\\\therefore 24 - 6 = 2x \\\therefore 18 = 2x \\ \therefore \: \frac{18}{2} = x \\ \therefore \: x = 9$

$\therefore AC = AB + BC\\\therefore 24 = x + x + 6\\\therefore 24 = 2x + 6\\\therefore 24 - 6 = 2x \\\therefore 18 = 2x \\ \therefore \: \frac{18}{2} = x \\ \therefore \: x = 9 \\ \because \: AB = x \\ \huge \red{ \therefore AB = 9} \\ \\ \because \:BC = x + 6 \\ \therefore \: BC = 9 + 6 \\ \huge \purple{ \therefore \: BC = 15}$

8 0

3 years ago

Write 4 tens and 3 hundredths as a decimal

mamaluj [8]

I believe it is written as 0.43 <span />

5 0

2 years ago

Read 2 more answers

Simplify the following

den301095 [7]

Answer:

1) 11 $\sqrt{3}$

2) 2 $\sqrt{2}$

3) $20\sqrt{3} + 15\sqrt{2}$

4) $53 + 12\sqrt{10}$

5) -2

6) $7\sqrt{2} - 5\sqrt{3}$

Step-by-step explanation:

1) 2 $\sqrt{12}$ + 3 $\sqrt{48}$ - $\sqrt{75}$

=(2 × 2 $\sqrt{3}$ )+ (3 × 4 $\sqrt{3}$ ) - 5 $\sqrt{3}$

= 4 $\sqrt{3}$ + 12 $\sqrt{3}$ - 5 $\sqrt{3}$

= 11 $\sqrt{3}$

2) 4 $\sqrt{8}$ -2 $\sqrt{98}$ + $\sqrt{128}$

= (4 × 2 $\sqrt{2}$ ) - (2 × 7 $\sqrt{2}$ ) + 8 $\sqrt{2}$

= 8 $\sqrt{2}$ - 14 $\sqrt{2}$ +8 $\sqrt{2}$

= 2 $\sqrt{2}$

3) 5 $\sqrt{12\\}$ - 3 $\sqrt{18} + 4 \sqrt{72} +2\sqrt{75}$

= 5× $2\sqrt{3}$ - 3× $3\sqrt{2}$ + 4× $6\sqrt{2}$ + 2× $5\sqrt{3}$

= $10\sqrt{3} - 9\sqrt{2} +24\sqrt{2} +10\sqrt{3}$

= $20\sqrt{3} + 15\sqrt{2}$

4) $(2\sqrt{2} + 3\sqrt{5} )^{2}$

= $8 + 12\sqrt{10} + 45$

= $53 + 12\sqrt{10}$

5) $(1+\sqrt{3} ) (1-\sqrt{3} )$

= $1 - 3$

= -2

6) $(2\sqrt{6} -1) (\sqrt{3} -\sqrt{2} )$

= $2\sqrt{18}-2\sqrt{12} -\sqrt{3} +\sqrt{2}$

= 2× $3\sqrt{2}$ - 2× $2\sqrt{3}$ - $\sqrt{3} + \sqrt{2}$

= $6\sqrt{2} - 4\sqrt{3} -\sqrt{3} +\sqrt{2}$

= $7\sqrt{2} - 5\sqrt{3}$

Hope the working out is clear and will help you. :)

5 0

2 years ago

Read 2 more answers

HEALTH B. Write T if the statement is true; and write F if the statement is false.

KIM [24]

Answer:

1.T

3.T

4.F

5.T

Step-by-step explanation

hope this helps

5 0

2 years ago

Find the measure of <br> a. 180 degrees<br> b. 149 degrees<br> c. 63 degrees<br> d. 32 degrees

Serhud [2]

Answer:

31 Degrees

Step-by-step explanation:

63+86= 149

180-149=31

6 0

2 years ago