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3 years ago

Use properties to evaluate the expression below.

Mathematics

1 answer:

Tpy6a [65]3 years ago

8 0

D. 9/5 hope this helped

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Simplify 8(a+2)+2(2+3a)

Alexxx [7]

Expand

8a + 16 + 4 + 6a

Collect like terms

(8a + 6a) + (16 + 4)

Simplify

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3 years ago

To derive the standard formula of a circle, a radius r is constructed as the hypotenuse of a right triangle as shown. On a coord

vlabodo [156]

Answer:

The answer is "x-h and y-k".

Step-by-step explanation:

The center is (h, k) with E (x, y) point, and its length of the legs used during extracting the standard circle equation should be found. Its right triangle length base is (x-h) units, as well as the right triangle's length, is (y-k). So, these are the required leg lengths, that's why the above-given points are correct.

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3 years ago

The domain for f (x) = 4x + 6 is {3,4,5). What is the range?

steposvetlana [31]

Answer:

The range is {18, 22, 26}

Step-by-step explanation:

5 0

3 years ago

H is directly proportional to the square root of p h=5.4 when p=1.44 find h when p=2.89

bazaltina [42]

Answer:

h=7.65

Step-by-step explanation:

h=k√p

k=h/√p

k=5.4/√1.44

k=4.5

h=4.5√p

when p=2.89

h=4.5√2.89

h=7.65

5 0

3 years ago

Read 2 more answers

A right triangle has side lengths a, b, and c as shown below.

Musya8 [376]

Answer:

$\bold{\sin x = \frac{b}{c}}\bold{\\\cos x = \frac{a}{c}}\bold{\\\tan x = \frac{b}{a}}$

Step-by-step explanation:

Given that

A right triangle has side lengths a, b, and c

Because you did not attached photo of the right triangle so I will assume that:

Side a is the adjacent (A)
Side b is the opposite (O)
Side c is the hypotenuse (H)

(Please have a look at the attached photo)

To solve for the trigonometric functions of x, we need to recall the ratios they represent as shown below.

$\sin x = \frac{O}{H}\\\cos x = \frac{A}{H}\\\tan x = \frac{O}{A}$

EX: the sine of x is equal to the side opposite of angle x over the hypotenuse. Hence, we have the expressions of the trigonometric functions as shown below:

$\bold{\sin x = \frac{b}{c}}\bold{\\\cos x = \frac{a}{c}}\bold{\\\tan x = \frac{b}{a}}$

Hope it will find you well

4 0

3 years ago