Since both are equivalent to y, the equations must be equivalent.
x^2-x-3= -3x+5
x^2+2x-8=0
(x+4)(x-2)=0
x=-4, x=2
Plug the values of x in to either equation
y=-3(-4)+5
y= 12+5
y=17
y= -3(2)+5
y=-6+5
y=-1
Final answer: (-4,17) and (2,-1)
Technically the endpoints will be intersection of first endpoint between x=1 and y=-1second endpoint between x=-2 and y=2
so they are 1-i and -2+2i
Answer: B. 33.1
Step-by-step explanation:
Use sin to solve (opposite/hypotenuse)
let x= length of CV
sin(37)=x/55
x=55sin(37)
x≈33.1
Answer:
B
Step-by-step explanation:
Both of them have the same variable and are both raised to the 5th power (Like the example in the last sentence of the text)
Answer:
(-3, 5) radius- r= 5
Step-by-step explanation:
x^2+6x+y^2-10y=-9
Rewrite ^2+6x+y^2-10y=-9 in the form of the standard circle equation
(x-(-3))^2+(y-5)^2= 5^2
Therefore the circle properties are:
(a, b)=(-3, 5), r= 5
