Ask question

Ask question

All categories

4 years ago

8

a 3,000kg truck runs into the rear of a 1000kg car that was stationary. The truck and car are locked together after the collisio

n and move with speed 9m/s what was the speed of the truck before the collision?

1 answer:

joja [24]4 years ago

7 0

FVJDJFN.s<ldF KN,M c":F,BJ TNHIJRT IHJYODIFG

You might be interested in

Help me please, MathPhys be my hero :)

Drupady [299]

Answer:

T = 261 K

T = -12.2°C

Explanation:

PV = nRT

If P and n are constant:

V / T = V / T

2.75 L / (273.15 + 21) K = 2.44 L / T

T = 261 K

T = -12.2°C

8 0

3 years ago

A straight, nonconducting plastic wire 8.00 cm long carries a charge density of 100 nC/m distributed uniformly along its length.

Sphinxa [80]

Answer:

(A) 16641 N/C (B) 72000 N/C

Explanation:

We have given the length of the wire = 8 cm =0.08 m

Charge density = 100 nC/m

So charge = 100 ×0.08 = 8 nC $=8\times 10^{-9}C$

(A) Electric field E that produce 6 cm directly above its midpoint will be

$E=\frac{KQ}{X\sqrt{X^2+a^2}}=\frac{9\times 10^9\times 8\times 10^{-9}}{0.06\sqrt{0.06^2+(\frac{0.08}{2})^2}}=16641N/C$

Here X is the distance where we have to find the electric field

(B) Now electric field due to flat ring will be

$E=\frac{KQX}{(X^2+a^2)^\frac{3}{2}}$

Here X is the distance where we have to find the electric field

So $E=\frac{9\times 10^9\times 8\times 10^{-9}}{(0.06^2+0.08^2)^\frac{3}{2}}=72000N/C$

7 0

4 years ago

When a person floating in swimming pool, they experience an upthrust. what causes this effect?

velikii [3]

When your head sticks out of the water the upthrust reduces as your head is no longer displacing water, and there is 0 resultant force so you float at that level. hope this helps, can i get brainliest please

6 0

4 years ago

The property of water that contributes to its ability to stick to certain surfaces is called

Gekata [30.6K]

Answer: Adhesion

Explanation: Adhesion is the tendency of dissimilar particles or surfaces to cling to one another (cohesion refers to the tendency of similar or identical particles/surfaces to cling to one another). The forces that cause adhesion and cohesion can be divided into several types. This allows Particles in things like water to stick to surfaces

3 0

3 years ago

A comet is traveling through space with speed 3.01 ✕ 104 m/s when it encounters an asteroid that was at rest. The comet and the

Tcecarenko [31]

Answer: $8.493(10)^{-3} m/s$

Explanation:

According to the conservation of linear momentum principle, the initial momentum $p_{i}$ (before the collision) must be equal to the final momentum $p_{f}$ (after the collision):

$p_{i}=p_{f}$ (1)

In addition, the initial momentum is:

$p_{i}=m_{1}V_{1}+m_{2}V_{2}$ (2)

Where:

$m_{1}=1.71(10)^{14} kg$ is the mass of the comet

$m_{2}=6.06(10)^{20} kg$ is the mass of the asteroid

$V_{1}=3.01(10)^{4} m/s$ is the velocity of the comet, which is positive

$V_{2}=0 m/s$ is the velocity of the asteroid, since it is at rest

And the final momentum is:

$p_{f}=(m_{1}+m_{2})V_{f}$ (3)

Where:

$V_{f}$ is the final velocity

Then :

$m_{1}V_{1}+m_{2}V_{2}=(m_{1}+m_{2})V_{f}$ (4)

Isolating $V_{f}$ :

$V_{f}=\frac{m_{1}V_{1}}{m_{1}+m_{2}}$ (5)

$V_{f}=\frac{(1.71(10)^{14} kg)(3.01(10)^{4} m/s)}{1.71(10)^{14} kg+6.06(10)^{20} kg}$

Finally:

$V_{f}=8.493(10)^{-3} m/s$ This is the final velocity, which is also in the positive direction.

8 0

4 years ago