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Rasek [7]
3 years ago
8

a 3,000kg truck runs into the rear of a 1000kg car that was stationary. The truck and car are locked together after the collisio

n and move with speed 9m/s what was the speed of the truck before the collision?
Physics
1 answer:
joja [24]3 years ago
7 0
FVJDJFN.s<ldF KN,M c":F,BJ TNHIJRT IHJYODIFG 
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If a force of 40N is applied for 0.2 sec to change the momentum of a volleyball, what is the impulse?
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Answer:

8ns

Explanation:

40(0.2)

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What is another word that can be used to describe the position of the<br> object?
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where the object is located

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A particle with charge 8 µC is located on the x-axis at the point −10 cm , and a second particle with charge 3 µC is placed on t
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Answer:Force on -7 uC charge due to charge placed at x = - 10cm

now we will have

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similarly force due to -5 uC charge placed at x = 6 cm

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Now net force on 7 uC charge is given as

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3 years ago
An electron of mass 9.11 1031 kg has an initial speed of 3.00 105 m/s. It travels in a straight line, and its speed increases to
elena55 [62]

Explanation:

It is given that,

Mass of an electron, m=9.11\times 10^{-31}\ kg

Initial speed of the electron, u=3\times 10^5\ m/s

Final speed of the electron, v=7\times 10^5\ m/s

Distance, d = 5 cm = 0.05 m

(a) The acceleration of the electron is calculated using the third equation of motion as :

a=\dfrac{v^2-u^2}{2d}

a=\dfrac{(7\times 10^5)^2-(3\times 10^5)^2}{2\times 0.05}

a=4\times 10^{12}\ m/s^2

Force exerted on the electron is given by :

F=m\times a

F=9.11\times 10^{-31}\times 4\times 10^{12}

F=3.64\times 10^{-18}\ N

(b) Let W is the weight of the electron. It can be calculated as :

W=mg

W=9.11\times 10^{-31}\times 9.8

W=8.92\times 10^{-30}\ N

Comparison,

\dfrac{F}{W}=\dfrac{3.64\times 10^{-18}}{8.92\times 10^{-30}}

\dfrac{F}{W}=4.08\times 10^{11}

Hence, this is the required solution.

8 0
4 years ago
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