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Alchen [17]
3 years ago
11

Write a message to Mr. Chang explaining why the groundwater heating system will warm the school more than the water heater syste

m. Use evidence to support your claim. For each piece of evidence you use, explain how the evidence supports your claim.
Physics
2 answers:
kari74 [83]3 years ago
8 0

Explanation:

For, heating purposes more the quantity of  water more will be the heating. Clearly, underground heating would have more water and hence, it will have edge over the  water heater system.

Moreover, for things at the same temperature, the thing with more molecules has more total kinetic energy (thermal energy) than the thing with fewer molecules. The groundwater heating system uses heat from the heat stored naturally in groundwater or aquifers. Thus, saving the cost of power required to heat in normal water heater.

dlinn [17]3 years ago
7 0

Answer:

For, heating purposes more the quantity of  water more will be the heating. Clearly, underground heating would have more water and hence, it will have edge over the  water heater system.

Moreover, for things at the same temperature, the thing with more molecules has more total kinetic energy (thermal energy) than the thing with fewer molecules. The groundwater heating system uses heat from the heat stored naturally in groundwater or aquifers. Thus, saving the cost of power required to heat in normal water heater.

Explanation:

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What is the speed of an object that moves 100 km in 45 minutes?
lana [24]
133 kilometers per hour
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A heavy boy and a lightweight girl are balanced on a massless seesaw. If they both
Len [333]

Answer:

D. Nothing will happen; the seesaw will still be balanced.

Explanation:

D. Nothing will happen; the seesaw will still be balanced. Since both toruqes or momentums respect to the center have changed in the same amount (one-half their original distance) the seesaw will remain balanced, if the children change distance in a different amount then it will be out of balance

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3 years ago
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When a driver touches a car’s steering wheel on a hot day, heat is transferred to the driver’s hands by ___________?
Alik [6]

The correct answer to this question is : C) Conduction

EXPLANATION:

Before coming into any conclusion, first we have to understand conduction.

Conduction is the mode of transmission of heat in which heat will flow from a body at high temperature to a body at low temperature in contact or from hotter part of the body to its colder part, without any actual transport of particles.

As per the question, the heat is transferred to driver's hand when he touches the steering wheel.

As there is actual contact between hand and steering wheel, the heat transmission will be conduction.

8 0
3 years ago
Read 2 more answers
A rocket accelerates upward from rest, due to the first stage, with a constant acceleration of a1 = 67 m/s2 for t1 = 39 s. The f
Igoryamba

Answer:

(a) v_1= a_1t_1

(b) v_2 =a_1t_1+a_2t_2

(c) 44133.5 m

Explanation:

<u>Given:</u>

  • u = initial speed of the rocket in the first stage = 0 m/s
  • v_1 = final speed of the rocket in the first stage
  • v_2 = final speed of the rocket in the second stage
  • t_1 = time interval of the first stage
  • t_2 = time interval of the second stage
  • s_1 = distance traveled by the rocket in the first stage
  • s_2 = distance traveled by the rocket in the second stage
  • s = distance traveled by the rocket in whole time interval

Part (a):

Since the rocket travels at constant acceleration.

\therefore v_1 = u+a_1t_1\\\Rightarrow v_1 = a_1t_1

Hence, the expression of the rocket's speed at time t_1\ is\ v_1 = a_1t_1.

Part (b):

In this part also, the rocket moves with a constant acceleration motion.

\therefore v_2 = v_1+a_2t_2\\\Rightarrow v_2 = a_1t_1+a_2t_2

Hence, the expression of the rocket's speed in the time interval t_2 is v_2 = a_1t_1+a_2t_2.

Part (c):

For the constant acceleration of rocket, let us first calculate the distance traveled by the rocket in both the time intervals.

s_1 = u+\dfrac{1}{2}a_1t_1^2\\\Rightarrow s_1 = 0+\dfrac{1}{2}67\times(1)^2\\\Rightarrow s_1 =33.5\ m

Similarly,

s_2 = v_1t_2+\dfrac{1}{2}a_2t_2^2\\\Rightarrow s_2 = a_1t_1t_2+\dfrac{1}{2}a_2t_2^2\\\Rightarrow s_2 = 67\times1\times49+\dfrac{1}{2}\times 34\times(49)^2\\\Rightarrow s_2 =44100\ m\\\therefore s = s_1+s_2\\\Rightarrow s = 33.5\ m+44100\ m\\\Rightarrow s =44133.5\ m

Hence, the rocket moves a total distance of 44133.5 m until the end of the second period of acceleration.

5 0
3 years ago
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Spaceship 1 and Spaceship 2 have equal masses of 300 kg. Spaceship 1 has an initial momentum magnitude of 600 kg-m/s. What is it
kati45 [8]

Answer:

Initial speed of the spaceship 1, v = 2 m/s

Explanation:

Given that :

Mass of spaceship 1 and 2 that have equal mass are 300 kg

Initial momentum of the spaceship 1 is 600 kg-m/s

To find :

We need to find the initial momentum of spaceship 1.

Solve :

The momentum of an object is equal to the product of mass and its velocity. Its SI unit is kg-m/s. Mathematically, it is given by :

p=mv

v=\dfrac{p}{m}

v=\dfrac{600\ kg-m/s}{300\ kg}

v = 2 m/s

Therefore the initial speed of spaceship 1 is 2 m/s. Hence, this is the required solution.

6 0
3 years ago
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