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Naddik [55]
3 years ago
11

Plz help quickly !!!!! answer soon

Mathematics
1 answer:
vitfil [10]3 years ago
8 0

Answer:

2/3, 1, and 6/5

Step-by-step explanation:

This is all just a matter of substitution. The values given of x = 1, x = 4/9 and x = 1 1/3 just need to be substituted in as x itself.

If x = 1, then the expression will be as the following: 4/15÷1+0.4. Dividing anything by 1 is just the same number, so 4/15 remains the same. 0.4 as a fraction is 4/10. A common denominator is 30, as both 10 and 15 fit into 30, so:

8/30+12/30=20/30, which can be simplified into 2/3

If x = 4/9, then we just substitute again. 4/15÷4/9+0.4. Due to BIDMAS, we do 4/15÷4/9 first, and to divide fractions, we use the KCF rule of Keep, Flip, and Change. We Keep the first fraction (4/15), Change the division sign into multiplication and then Flip the second fraction so it becomes 9/4

Now, we multiply the two fractions (4/15×9/4) to get 3/5, and then adding 4/10 to that gives us just 1.

If x = 1 1/3, we do the exact same thing we did for x = 4/9 to get 6/5. Good luck.

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The first derivative is 5
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Can someone explain how to solve this I'm really confused <br><br> 1/2 to the power of 3
OleMash [197]

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1/8

Step-by-step explanation:

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5 0
3 years ago
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Jerome will be buying a used car for $11,000 in 4 years. How much money should he ask his parents for now so that, if he invests
hjlf

Answer:

$7,987.64

Step-by-step explanation:

We know,

A = Pe^(rt)

Here,

A = 11000  

interest r = .08

Time t = 4

Now,

11000 = Pe^(.08 * 4)

Or, 11000 = Pe^.32  

Or, 11000 / e^.32 = P

Or, 7987.6394 = P

Or, P= 7,987.64

Jerome will have to ask for $7,987.64 to his parents.  

4 0
4 years ago
What two numbers have a product of -2 and a sum of 7
Citrus2011 [14]

<em>Greetings from Brasil...</em>

According to the statement of the question, we can assemble the following system of equation:

X · Y = - 2      i

X + Y = 7       ii

isolating X from i and replacing in ii:

X · Y = - 2

X = - 2/Y

X + Y = 7

(- 2/Y) + Y = 7     <em>multiplying everything by Y</em>

(- 2Y/Y) + Y·Y = 7·Y

- 2 + Y² = 7X     <em> rearranging everything</em>

Y² - 7X - 2 = 0      <em>2nd degree equation</em>

Δ = b² - 4·a·c

Δ = (- 7)² - 4·1·(- 2)

Δ = 49 + 8

Δ = 57

X = (- b ± √Δ)/2a

X' = (- (- 7) ± √57)/2·1

X' = (7 + √57)/2

X' = (7 - √57)/2

So, the numbers are:

<h2>(7 + √57)/2</h2>

and

<h2>(7 - √57)/2</h2>
7 0
4 years ago
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