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Phoenix [80]
3 years ago
8

Brian's kite is flying above a field at the end of a 68m string.If the angle of elevation to the kite measures 70 degrees,how hi

gh is the kite above Brian's head?

Mathematics
1 answer:
Dvinal [7]3 years ago
4 0

Answer:

h = 63.92\ m

Step-by-step explanation:

Given:

Angle of elevation = 70°

Length of string = 68 m

We need to find the height of the kite.

Solution:

Requirement figure attached in file.

Where:

BC = 68 m

AC = h (Height of the kite)

∠ABC = 70°

Using Cosine rule to find the height of the kite.

AC = BC\times sin(70)

h = 68\times 0.94

h = 63.92\ m

Therefore, height of the kite from Brian's head h = 63.92\ m.

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The original price of a car is $25000. Each year, its value depreciates (loses value) by 13%. Three years after its purchase, wh
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5 0
3 years ago
I need help to solve it
Sidana [21]

Answer:

She will earn £9.01 per hour after the pay rise

Step-by-step explanation:

Here, we want to calculate a value, given the percentage of the pay rise

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8.50 + 6% of 8.50

= 8.50 + (6*8.5)/100

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4 0
3 years ago
On the first day in each month, Enid deposited $4 into her bank account and Jim deposited $3 into his. They opened these account
ohaa [14]

Answer:

The amount of money in Enid bank account can be written as a linear equation.

Ye = Xe + $4*m

where Ye is the money that Enid has in her account, m is the number of months that have passed since she opened it, and Xe is the initial deposit.

For Jim, the equation is similar:

Yj = Xj + $3*m

where Yj and Xj are similar as above.

Between May 15 and December 31 of the same year, we have 7 months (where i am counting December because the deposit is made in the first day of the month).

Then we have that:

Ye = $72 = Xe + $4*7 = Xe + $28

Xe = $72 - $28 = $44

So in May 15, Enid deposited $44.

For Jim we have:

Yj = $72 = Xj + $3*7 = Xj + $21

Xj = $72 - $21 = $51

So in May 15, Jim deposited $51.

5 0
2 years ago
A company makes wax candles in the shape of a solid sphere. Suppose each candle has a diameter of 15 cm. If
jekas [21]

We have been given that a company makes wax candles in the shape of a solid sphere. Each candle has a diameter of 15 cm. We are asked to find the number of candles that company can make from 70,650 cubic cm of wax.

To solve our given problem, we will divide total volume of wax by volume of one candle.

Volume of each candle will be equal to volume of sphere.

V=\frac{4}{3}\pi r^3, where r represents radius of sphere.

We know that radius is half the diameter, so radius of each candle will be \frac{15}{2}=7.5 cm.

\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot (7.5\text{ cm})^3

\text{Volume of one candle}=\frac{4}{3}\cdot 3.14\cdot 421.875\text{ cm}^3

\text{Volume of one candle}=1766.25\text{ cm}^3

Now we will divide 70,650 cubic cm of wax by volume of one candle.

\text{Number of candles}=\frac{70,650\text{ cm}^3}{1766.25\text{ cm}^3}

\text{Number of candles}=\frac{70,650}{1766.25}

\text{Number of candles}=40

Therefore, 40 candles can be made from 70,650 cubic cm of wax.

8 0
3 years ago
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