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ValentinkaMS [17]
1 year ago
13

Find the slope (-10,8) (5,-3)

Mathematics
1 answer:
Anarel [89]1 year ago
8 0

The slope can be calculated with the following formula:

m=\frac{y_2-y_1}{x_2-x_1}

In this case, you have the following points:

undefined

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A rectangular garden has a length that is
skelet666 [1.2K]

Answer:

Since,

Length is 4 times Breadth

Let Breadth be x

Therefore,Length=4x

Perimeter=50m

Therefore,

50m=2(l+b)

50m=2(4x+x)

50m=2(5x)

50m=10x

x=5m.

Therefore,

Breadth=5m

Length=4x=4×5=20m

6 0
2 years ago
The equations of two lines are x - 3y = 6 and y = 3x + 2. determine if the lines are parallel, perpendicular or neither.parallel
Mice21 [21]
Start by converting x - 3y = 6 into slope-intercept form:
x - 3y = 6
Subtract x from both sides:
-3y = -x + 6
Divide both sides by -3:
y = (1/3)x - 2
Now compare both equations:
y = (1/3)x - 2
y = 3x + 2
They don't share anything perpendicular or parallel equations would share, so therefore they are neither.

Hope this helps! :)
6 0
3 years ago
A jet flew at a constant of 350 miles per hour for 6 hours and 30 minutes. What distance did the jet travel?
dsp73
The answer is D.

350 multiplied by 6 is equal to 2100

350 * 0.5 (30 minutes) is equal to 175

2100 + 175 = 2275 
5 0
2 years ago
Read 2 more answers
Expand and simplify (2x−12) ^2
lubasha [3.4K]

Answer:

\boxed{4x^{2}  - 48x + 144}

Step-by-step explanation:

Given expression:

  • (2x - 12)²

To simplify the expression, we will use the formula (a - b)² = a² - 2ab + b².

[Where "a and b" are the first and second term in (a - b)²]

\rightarrowtail (2x - 12)^{2}

In this case, the first term of (2x - 12)² is "2x" and the second term is "12".

\rightarrowtail (2x)^{2} - 2(2x)(12) + (12)^{2} \ \ \ \ \ \ \ \ \ \ \ \ \ \  [\small\text{First term = a = 2x; Second term = b = 12]}

Now, simplify the expression.

\rightarrowtail (2x)^{2} - 2(2x)(12) + (12)^{2}

\rightarrowtail (2x)(2x) - (4x)(12) + (12)(12)

\rightarrowtail \boxed{4x^{2}  - 48x + 144}

4 0
2 years ago
The accompanying data contains the depth​ (in kilometers) and​ magnitude, measured using the Richter​ Scale, of all earthquakes
Sunny_sXe [5.5K]

Answer:

Depth:

μ =20.2025 km

M = 15.625 km

Range = 47.15 km

σ ≈ 15.92 km

Q₁ = 5.7375 km

Q₃ =  34.6675 km

Magnitude:

μ = 2.08375

M = 1.465

Range, R = 5.17

σ = 1.801485 ≈ 1.8

Q₁ = 0.5625

Q₃ = 3.925

Step-by-step explanation:

The given data are;

Depth {}                                 Magnitude

0.76 {}                                    0.84

4.93 {}                                    0.47

8.16 {}                                     0.35

33.58 {}                                  1.32

21.2 {}                                     1.61

35.03 {}                                  4.57

10.05 {}                                   5.52

47.91 {}                                    1.99

For the Depth, we have;

The mean, μ = (0.76+4.93+8.16+33.58+21.2+35.03+10.05+47.91)/8 =20.2025 km

The median, M = The (n + 1)/2th term after arranging the term in increasing order as follows;

0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91 , the median is therefore;

(8 + 1)/2th term or the 4.5th term which is 10.05 + (21.2 - 10.05)/2 = 15.625 km

The Range = The highest - The lowest value = 47.91 - 0.76 = 47.15 km

The Standard deviation of, σ, is given as follows;

\sigma =\sqrt{\dfrac{\sum \left (x_i-\mu  \right )^{2} }{N}}

Where;

x_i = The individual data point = (0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91 )

N = The total number of data point = 8

Substituting, (using Microsoft Excel) we get;

\sigma =\sqrt{\dfrac{\sum \left (x_i-20.2025  \right )^{2} }{8}} \approx 15.92 \ km

Q₁ = The first quartile = The (n + 1)/4th =  term arranged in increasing order

Q₁ = The (8 + 1)/4th term = The 2.25th term = 4.93 + (8.16 - 4.93)×0.25) = 5.7375 km

Q₃ = The first quartile = The 3×(n + 1)/4th =  term arranged in increasing order

Q₃ = The 3×(8 + 1)/4th term = The 6.75th term = 33.58 + 3×(35.03 - 33.58)×0.25) = 34.6675 km

For the magnitude, we have, using the same formulas and procedures as above;

μ = 2.08375

M = 1.465

Range, R = 5.17

σ = 1.801485 ≈ 1.8

Q₁ = 0.5625

Q₃ = 3.925

4 0
3 years ago
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