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Keith_Richards [23]
3 years ago
10

You are given 1000 one dollar bills and 10 envelopes. Put the bills into the envelopes in such a way that someone can ask you fo

r any amount of money from $1 to $1000 (examples - $532, $619, $88, etc.) and you can give it to them through a combination of the envelopes.
Mathematics
1 answer:
taurus [48]3 years ago
4 0

Answer:

We can do it with envelopes with amounts $1,$2,$4,$8,$16,$32,$64,$128,$256 and $489

Step-by-step explanation:

  • Observe that, in binary system, 1023=1111111111. That is, with 10 digits we can express up to number 1023.

This give us the idea to put in each envelope an amount of money equal to the positional value of each digit in the representation of 1023. That is, we will put the bills in envelopes with amounts of money equal to $1,$2,$4,$8,$16,$32,$64,$128,$256 and $512.

However, a little modification must be done, since we do not have $1023, only $1,000. To solve this, the last envelope should have $489 instead of 512.

Observe that:

  1. 1+2+4+8+16+32+64+128+256+489=1000
  2. Since each one of the first 9 envelopes represents a position in a binary system, we can represent every natural number from zero up to 511.
  3. If we want to give an amount "x" which is greater than $511, we can use our $489 envelope. Then we would just need to combine the other 9 to obtain x-489 dollars. Since x-489\leq511, by 2) we know that this would be possible.

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What is the sum of (2a - 3b) and (5b - a)
GalinKa [24]

Answer:

\boxed{a + 2b}

Step-by-step explanation:

=  > (2a  - 3b) + (5b - a) \\  \\  =  > 2a - 3b + 5b - a \\  \\  =  > 2a - a + 5b - 3b \\  \\  =  > a + 2b

8 0
3 years ago
A crane lifts an air conditioner weighing 800 Newtons up to the roof of a building in New York City. It took one minute to raise
tia_tia [17]

Answer:

160,000 Nm

2667 Nm/sec

Step-by-step explanation:

Work = weight * distance

= 800 * 200

= 160,000 Nm

Power = rate of work done

= 160,000 / 60

=  2667 Nm/sec

4 0
3 years ago
The sum of two numbers is 11. The sum of their squares is 65. Find the numbers. (How do you get the answer?)
Stels [109]
X is the number
<span>The sum of two numbers is 11, so other number is : 11 - x

</span><span>The sum of their squares is 65
</span>
x^2 + (11 - x)^2 = 65
x^2 + 121 - 2(x)(11) + x^2 = 65
2x^2 - 22x + 121 = 65
2x^2 - 22x + 121 -  65 = 0
2x^2 - 22x + 56 = 0
2(x^2 - 11x + 28) = 0
2(x - 7)(x -4 ) = 0
x - 7 = 0
x = 7

x - 4 =0
x =4

answer: the numbers are 4 and 7

double check:

<span>sum of two numbers is 11:
4 + 7 = 11

</span><span>The sum of their squares is 65
</span><span>4^2 + 17^2 = 16 + 49 = 65

</span>
7 0
3 years ago
R --&gt; 2 P. Initially you start off with 0.5 M reactants and let the reaction run to equilibrium and calculate the equilibrium
Anit [1.1K]

Answer:

K still the same value

Step-by-step explanation:

given a reaction aA+bB<->cC+dD the constant K is defined as:

\frac{C^{c}D^{d}  }{A^{a}B^{b} }

K is a constant so it won't change the value. Instead, the values of C and D are going to change.  The position of equilibrium moves because of the need to keep a constant value for the equilibrium constant.

8 0
3 years ago
a bag of potting soil costs $3 less than a flower pot. Ike paid $41 for 3 flower pots and 5 bags of soil. how much does one bag
Arada [10]
Cost of bag of soil = x-3 where x is the price of a flower pot
41=3x + 5(x-3)
41=3x + 5x -15
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41+15=8x
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56÷8=x
$7.00=x
5 0
3 years ago
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