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3 years ago

PLZZZ HELPPPPPPP LAST QUESTIONS LAST CHANCE FOR POINTSSSS REWARD BRAINLIESTT

Mathematics

2 answers:

vlada-n [284]3 years ago

8 0

Answer:

17)x=12, -7

18)x=+2, -2

19)(2x-5)(3x+1)

20)3(5x+4)(x-2)

Step-by-step explanation:

17) (x-12)(x+7)=0

x=12, -7

18)3x^2-12=0

3x^2=12

x^2=4

x=+2, -2

19)(ax+b)(cx+d)

Ax^2+Bx+C

A=6, B=-13, C=-5

ac=6

ad+bc=-13

bd=-5

a=2

b=-5

c=3

d=1

(2x-5)(3x+1)

20)3(5x^2-6x-8)

=3(5x+4)(x-2)

Hope I helped! And also, is this really college math? I'm in middle school and I know how to do it!

Can you give me brainliest, since I did all of them?

Nimfa-mama [501]3 years ago

3 0

Answer:

question 19

(2x-5)(3x+1)

Step-by-step explanation:

question 19

6x^2-13x-5

6x^2 coefficient = 6

-13x coeddicient = -13

-5 is constant

multiply coefficient of first term by the constant

i.e. 6*-5= -30

get 2 factors of -30 whoose sum equals -13

-15 +2 = -13

rewrite to have

6x^2-15x+2x-5

3x(2x-5) the firs term

1(2x-5)

add up,

(3x+1)(2x-5)

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torisob [31]

Step-by-step explanation:

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6 0

3 years ago

Factor 6x2 + 192 + 3

skad [1K]

Answer:

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Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

1.How many combinations are possible from the letters HOLIDAY if the letters are taken?

Lesechka [4]

Using the combination formula, it is found that:

1. A. 7 combinations are possible.

B. 21 combinations are possible.

C. 1 combination is possible.

2. There are 245 ways to group them.

<h3>What is the combination formula?</h3>

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Exercise 1, item a:

One letter from a set of 7, hence:

$C_{7,1} = \frac{7!}{1!6!} = 7$

7 combinations are possible.

Item b:

Two letters from a set of 7, hence:

$C_{7,2} = \frac{7!}{2!5!} = 21$

21 combinations are possible.

Item c:

7 letters from a set of 7, hence:

$C_{7,7} = \frac{7!}{0!7!} = 1$

1 combination is possible.

Question 2:

Three singers are taken from a set of 7, and four dances from a set of 10, hence:

$T = C_{7,3}C_{10,4} = \frac{7!}{3!4!} \times \frac{10!}{4!6!} = 245$

There are 245 ways to group them.

More can be learned about the combination formula at brainly.com/question/25821700

6 0

2 years ago

PLS HELP ME ASAP WITH NUMBER 37

Reil [10]

A) The equations are shown on the attached graph.
x = juice box cost
y = water bottle cost

B) Kara's proposed solution satisfies the first equation, but not the second one.

C) The solution is shown on the attached graph.

____
As a bonus, you get a graph for the other problem you posted. Please note this graph has some issues. Wherever there's a solid line ⌝ or ⌞ the actual shape of the graph should be the opposite one of these.