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Alex
3 years ago
15

PLZZZ HELPPPPPPP LAST QUESTIONS LAST CHANCE FOR POINTSSSS REWARD BRAINLIESTT

Mathematics
2 answers:
vlada-n [284]3 years ago
8 0

Answer:

17)x=12, -7

18)x=+2, -2

19)(2x-5)(3x+1)

20)3(5x+4)(x-2)

Step-by-step explanation:

17) (x-12)(x+7)=0

x=12, -7

18)3x^2-12=0

3x^2=12

x^2=4

x=+2, -2

19)(ax+b)(cx+d)

Ax^2+Bx+C

A=6, B=-13, C=-5

ac=6

ad+bc=-13

bd=-5

a=2

b=-5

c=3

d=1

(2x-5)(3x+1)

20)3(5x^2-6x-8)

=3(5x+4)(x-2)

Hope I helped! And also, is this really college math? I'm in middle school and I know how to do it!

Can you give me brainliest, since I did all of them?

Nimfa-mama [501]3 years ago
3 0

Answer:

question 19

(2x-5)(3x+1)

Step-by-step explanation:

question 19

6x^2-13x-5

6x^2 coefficient = 6

-13x coeddicient = -13

-5 is constant

multiply coefficient of first term by the constant

i.e. 6*-5= -30

get 2 factors of -30 whoose sum equals -13

-15 +2 = -13

rewrite to have

6x^2-15x+2x-5

3x(2x-5) the firs term

1(2x-5)

add up,

(3x+1)(2x-5)

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Answer this plz!!!!!!!!!!
belka [17]

That's a trapezoid,

A = \frac 1 2 (b+B)h

A = \frac 1 2 (4+12) 4 = 32

Answer: 32

But say we didn't know the formula. We can chop out the 4 by 4 square and we have two 45/45/90 triangles side 4 left over, so two 4 by 4 squares,

A = 2(4)(4) = 32

We can think of this as 12 by 4 rectangle with two 4 by 4 right triangles chopped out:

A = 12(4) - 2(1/2)(4)(4) = 48 - 16 = 32


7 0
3 years ago
) Picture frames are produced such that the four sides of a picture frame consist of two pieces from a population whose mean len
Natali [406]

Answer:

The mean perimeter of frame = 38 cm

Step-by-step explanation:

By perimeter of a rectangle, the formula is given as:

Perimeter of rectangle = 2(A + B)

Going by the illustration in the question, the perimeter is

==> 2(32 + 44) = 152 cm.

However, we a given the mean perimeter of the frame which are:

32 and 44. We can either choose to say; each sides is (32 by 32) and (44 by 44). Or we consider it in mean/average term as given: (32 by 44).

Case 1: To obtain the mean perimeter of the frame using the first scenario, we say:

Mean perimeter = (32+32+44+44)/4 = 38 cm.

Case 2: We can simply say:

Mean perimeter = (32 + 44)/2 = 38 cm.

Graphically: Assuming that the frame is given below

                     32 cm

          ---------------------------------

         |                                      |

         |                                      |

44 cm|                                      | 44 cm

         |                                      |

         |                                      |

         |                                      |

         ----------------------------------

                       32 cm

The mean of upper frame/bars = 32 cm

The mean of side frame/bars  =  44 cm

Hence, the mean of the perimeter = (32 + 44)/2 = 38 cm

OR,

we take the sum of all the sides (32 + 44 + 32 + 44) and divide by total number of sides (4). That is;

The mean of the perimeter = (32 + 44 + 32 + 44)/4 = 38 cm

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