Complete question :
The birthweight of newborn babies is Normally distributed with a mean of 3.96 kg and a standard deviation of 0.53 kg. Find the probability that an SRS of 36 babies will have an average birthweight of over 3.9 kg. Write your answer as a decimal. Round your answer to two places after the decimal
Answer:
0.75151
Step-by-step explanation:
Given that :
Mean weight (m) = 3.96kg
Standard deviation (σ) = 0.53kg
Sample size (n) = 36
Probability of average weight over 3.9
P(x > 3.9)
Using the z relation :
Zscore = (x - m) / (σ / √n)
Zscore = (3.9 - 3.96) / (0.53 / √36)
Zscore = - 0.06 / 0.0883333
Zscore = −0.679245
Using the Z probability calculator :
P(Z > - 0.679245) = 0.75151
= 0.75151
Answer:
The slope is 2.
Step-by-step explanation:
Slope = rise / run, meaning that when you move 2 units up, you move 1 unit right. The slope here is positive.
Answer:
1245
Step-by-step explanation:
You have to multiply 415 and 3, since 10 x 3 = 30
415 x 3 = 1245
Answer:
The least cost of fencing for the rancher is $1200
Step-by-step explanation:
Let <em>x</em> be the width and <em>y </em>the length of the rectangular field.
Let <em>C </em>the total cost of the rectangular field.
The side made of heavy duty material of length of <em>x </em>costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are <em>x, y, y</em>. Thus

We know that the total area of rectangular field should be 2250 square yards,

We can say that 
Substituting into the total cost of the rectangular field, we get

We have to figure out where the function is increasing and decreasing. Differentiating,

Next, we find the critical points of the derivative

Because the length is always positive the only point we take is
. We thus test the intervals
and 

we see that total cost function is decreasing on
and increasing on
. Therefore, the minimum is attained at
, so the minimal cost is

The least cost of fencing for the rancher is $1200
Here’s the diagram:
So hmmm let's see
she has a monthly income of 120 from investments, now, there are 12 months in a year, so her yearly income from investments are 120*12 or
$1440
she plays on a band, and makes 200 a week, now, there are 52 weeks in a year, so her yearly income from band playing is 200 * 52, or
$10400
her total annual income is 49696, now, if we subtract the band and investment income, we'd be left over with only what comes from her job payrate
so 49696 - 1440 - 10400 is 37856
so, she makes from her job, $37856 annually
now, she only works 28 hours weekly, how much is that yearly? well, 52 weeks in a year, she works 28*52 hours a year, let us divide 37856 by that
37856 ÷ ( 28 * 52) well, it ends up as 26
so, her hourly payrate is $26 per hour
now, she wants to ask for a raise, to make 51880 annually
well, if we check the difference of 51880 and 49696, that'd leave us with the difference in pay, or the raise annual amount
51880 - 49696 = 2184
ok, so she wants $2184 annually more from her work
how much is that in the hours she works annually? well 2184 ÷ ( 28 * 52)