Cables are forming 3 right angled triangles the pole being the shared height of them;
(height) b= 12yd
(base) a= 9yd
(hypotenuse) c= ?
Need to find the long side (hypotenuse);
a^2 + b^2 = c^2
12^2 + 9^2 = 225
Take square root of 225 = 15
Then you have;
1x 12yd = 12
3x 9 yd = 27
3x 15yd = 45
Add them up = 84yd of cable needed
Answer:
Step-by-step explanation:
<u>Dimensions given:</u>
- l = 2 1/4 ft, w = 1 ft, h = 1 1/4 ft
A small cube has side of 1/4 ft
Find the number of small cubes can fit in each dimension of the prism.
<u>Length</u>
- 2 1/4 : 1/4 = 9/4 * 4 = 9
<u>Width</u>
<u>Height</u>
- 1 1/4 : 1/4 = 5/4 * 4 = 5
Part A
<u>Number of small cubes would be:</u>
Part B
<u>Each small cube has volume:</u>
The volume of the prism in terms of small cubes is 180 as we found above.
<u>The volume in terms of unit cube:</u>
- V = 180*1/64 = 180/64 = 2 52/64 = 2 13/16 ft³ or 2.8125 ft³
Answer:
sin a = 7/25
cos a = 24/25
tan a = 7/24
Step-by-step explanation:
Trig. How wonderful. I get tripped up on these types of problems some times, so I decided to try to help! To start, write out the three ratios.
SOH (sine=opposite/hypotenuse) CAH (cosine=adjacent/hypotenuse) TOA (tangent=opposite/adjacent)
Then, label the triangle with “hypotenuse” “adjacent” and “opposite.” This helps us correctly use and find the raitos. Then, use these ratios to find out the ratios of A!
sin a = 7/25
cos a = 24/25
tan a = 7/24
If needed, just divide the ratios to get their decimal form!
Three and six tenths
Hope I helped!
