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wariber [46]
3 years ago
6

smallest cube has a edge length of 6 inches. what are the lengths of the other cubes if the ratios of similarity to the smallest

cube are 1.25, 4/3, 1.5, 7/4 and 2 respectively
Mathematics
1 answer:
serg [7]3 years ago
8 0
<span>The ratio of similarity is simply the number you multiply by to scale from one similar object to another. Since you've been told the smallest object has an edge length of 6 inches, just multiply each of the ratios by 6 to get the length of their edge. So 1.25: 1.25 * 6 inches = 7.5 inches 4/3: 4/3 * 6 inches = 24/3 inches = 8 inches 1.5: 1.5 * 6 inches = 9 inches 7/4: 7/4 * 6 inches = 42/4 inches = 21/2 inches = 10.5 inches 2: 2 * 6 inches = 12 inches</span>
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A fish swims over the waterfall. The distance y (in feet) that the fish falls is given by the function y=16t2 , where t is the t
inessss [21]

Answer:

See Explanation

Step-by-step explanation:

Given

y = 16t^2

The equation is incomplete. However, a possible question could be to calculate the distance of the fish at a particular time

e.g. Time, t = 4,

The distance is:

y = 16t^2

y = 16 * 4^2

y = 16 * 16

y = 256ft

Another possible question is to determine the time taken to cover a certain distance

e.g.

Distance, y = 400

This gives:

y = 16t^2

400 = 16t^2

Divide by 16

25 = t^2

Take square roots

5 = t

t = 5\ seconds

8 0
3 years ago
) f) 1 + cot²a = cosec²a​
notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}

Another identity is:

\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}

Therefore:

\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}

Another identity:

\displaystyle \large{\sin^2x+\cos^2x=1}

Therefore:

\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}

Hence proved, this is proof by using identity helping to find the specific identity.

6 0
3 years ago
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soldier1979 [14.2K]

Yes. It's a linear function.

<u>x | y</u>

<u>0| 2(0) = 0</u>

<u>1| 2(1) = 2</u>

<u>2| 2(2) = 4</u>

3 0
3 years ago
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pickupchik [31]

Answer:

1. 0/10

2. -9/0

Step-by-step explanation:

you want to do the second y- the first y / the second X-the first x

3 0
3 years ago
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denis23 [38]

Mean:

50

Median:

44

Mode:

35, 44, 77, 68, 43, 55, 2

5 0
3 years ago
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